Answer
given,
mass of the ball = 300 g
= 0.3 Kg
maximum altitude of the ball = 10.1 m
Potential energy of the softball:
PE = m g h
PE = 0.3 x 9.8 x 10.1
PE = 29.69 J
Maximum kinetic energy at which the ball is released from hand to reach height of 10.1 m is 29.69 J.
Kinetic energy at which ball returns to your hand is equal to 29.69 J.
speed of the ball
v² = 197.93
v = 14.069 m/s
Answer:
0.79 s
Explanation:
The initial velocity of the ball is, .
And now we know that first equation of motion.
Here, v is the final velocity, u is the initial velocity, t is time taken by the object, a is the acceleration.
Given that, final velocity is zero and ball is inb upward direction means opposite to acceleration due to gravity which means a=-g. and the value of g is
Therefore,
Therefore, it is the required minimum time that player must waiot to touch the ball.
I think your answer would Be A. Because historians mostly study written documents, while archaeologists uncover fossils and buildings.
Intensity. They relate the intensity of a pressure wave to a normal or standard pressure
Answer:
vpg = 0.064 N
Explanation:
Upthrust = Volume of fluid displaced
upthrust liquid on the cube g=10ms−2
vpg =0.2 x 0.2 x 0.2 x0.8 x 10= 0.064N
vpg = 0.064 N
hope it helps.