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Andreyy89
3 years ago
7

A substance with a high boiling point will also likely have A) a low melting point B) a low vapor pressure C) weak intermolecula

r interactions D) low surface tension E) low viscosity
Chemistry
1 answer:
UkoKoshka [18]2 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

Boiling point is defined as the temperature at which vapor pressure of a liquid becomes equal to the atmospheric pressure.

Surface tension is defined as the attractive forces experienced by the surface molecules of a liquid by the molecules present beneath the surface layer of the liquid. More stronger are the intermolecular forces present within the molecules of a liquid more will be its surface tension and lower will be its vapor pressure.

Hence, higher will be the boiling point of the liquid.

And, viscosity is defined as the ability of a liquid to resist its flow. When a substance has high viscosity then it is known as a viscous substance.

Thus, we can conclude that a substance with a high boiling point will also likely have a low vapor pressure.

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Viefleur [7K]

A 3.4 × 10⁶ L swimming pool must have a mass of 1.0 × 10⁷ mg Cl₂ to maintain a concentration of 3.0 ppm.

<h3>What is "ppm"?</h3>

"ppm" of "parts per million" is a unit of concentration equivalent to milligrams of solute per liters of solution.

A pool must maintain a chlorine concentration of 3.0 ppm (3.0 mg/L). The mass of chlorine in 3.4 × 10⁶ L is:

3.0 mg Cl₂/L × 3.4 × 10⁶ L = 1.0 × 10⁷ mg Cl₂

A 3.4 × 10⁶ L swimming pool must have a mass of 1.0 × 10⁷ mg Cl₂ to maintain a concentration of 3.0 ppm.

Learn more about ppm here: brainly.com/question/13395702

#SPJ1

4 0
2 years ago
The density of benzene at 15 °c is 0.8787 g/ml. Calculate the mass of 0.1500 l of benzene at this temperature. Enter your answer
Otrada [13]

Answer:

131.8 g.

Explanation:

  • There is a relation that relates the density of the substance (d) to the mass (m) and the volume of the substance (V):

<u><em>d = m / V.</em></u>

d = 0.8787 g/ml.

V = 0.15 L x 1000 = 150 ml.

  • ∴ the mass of 0.15 L of benzene = d x V = (0.8787 g/ml) (150 ml) = 131.8 g.
5 0
3 years ago
What changes within the star A lead to the red giant B?
Lady_Fox [76]

Answer: The fusion of hydrogen to form helium

Explanation:

8 0
3 years ago
A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.
solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

E = \frac{h \times c }{\lambda }

where,

  • h: Planck's constant
  • c: speed of light

E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s  \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

8 0
3 years ago
List two situations in which measurements have unlimited number of significant figures
GaryK [48]
Your answers would be, (Ex. 3*3*3*3....etc..).
(1), When measurements involving counting
(2), When measurement involves exactly defined quantities




Hope that helps!!!

5 0
3 years ago
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