s=600 m
t=12 s
s=0.5*a*t² (initial speed V0=0)
a=(2*s)/t²
a=(2*600)/12²
a≈8.33 m/s²
L= s(t2=12s)-s(t1=11s) -> (distance during the twelfth second)
L=0.5*a*(t2²-t1²)
L=0.5*((2*s)/t²)*(t2²-t1²)
L=0.5*((2*600)/12²)*(12²-11²)
L ≈ 95.83 m
All continental coastlines match up with continental drifts. As a matter of fact, you could literally cut out the continents from a map and put them together like a puzzle and they would fit. Easiest to notice is the west of Africa and the east of South America.
the question is missing another parameter. we need to know the time taken for the ball to come down. You can use the below formula to find the initial vertical speed.
S = 1/2at2 + ut
distance = 1/2 × acceleration × time2 + intial speed × time
