Answer:
The velocity of the boat and fisherman after he lands in the boat is 3.812m/s
Explanation:
We will solve this question on the general Derivation for general case of a man jumping n the boat
m = Mass of the man = 80kg
M= mass of the boat 37.5kg
V(m, g) = Velocity of man with respect to ground = 5.6m/s
V(b , g) = Velocity of boat with respect to ground = Vo = 0m/s ( rest)
velocity of the boat and fisherman after he lands in the boat = V1
As there is no external force acting on the man then we can apply conservation of the Linear Momentum.
m*V(m, g) + M*Vo = (M+m)V1
On substituting the values we get
V1 =
V1 = = 3.812 m/s
Therefore the velocity of the boat and fisherman after he lands in the boat is 3.812m/s.
change in velocity=final velocity-initial velocity=9-3=6m/s
acceleration=change in velocity/time
=6/3=2m/s²
B show the potential energy and the kenetic energy
Answer: current = 10.25A
Explanation:
Toward = 240w
Alarm clock = 30w
Tanning bed = 720w
4 60 watts bulb = 60 * 4 = 240w
Total power = 240 + 30 + 720 + 240 = 1230w
Voltage = 120v
Recall that Power = current * voltage
1230 = current * 120
current = 1230/120 = 10.25A
<span>The activation temperature of most ice-forming nuclei is "Below 0 C"
Hope this helps!</span>