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2 years ago

6

The gas in a cylinder has a volume of 3 liters at a pressure of 117 kpa. the pressure of the gas is increased to 219 kpa. assumi

ng the temperature remains constant, what would the new volume be?

1 answer:

solniwko [45]2 years ago

8 0

V = (1 / p) × p0×V0 = (1 / 219kPa) × 117kPa × 3L = 1.06L

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$F_{e} = \frac{G*5.97 * 10^{24} M }{d^{2} }$ ...............................(1)

The earth and the moon are separated by a distance, 3.844 * 10⁸ m

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Equating equations (1) and (2)

$\frac{5.97 * 10^{24} }{d^{2} } = \frac{7.348 * 10^{24} }{(3.844* 10^{8} -d)^{2} }$

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Factorising out $10^{24}$

$1.378d^{2} + 45.9 * 10^{8}d + 88.24*10^{16} = 0$

Solving for d in the quadratic equation above:

d = 346 * 10⁶ m

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