Answer:
Explanation:
mass of first marble ![m_1=m=0.015\ kg](https://tex.z-dn.net/?f=m_1%3Dm%3D0.015%5C%20kg)
Initial velocity of the first marble
considering right side as positive
Mass of second marble
After collision first marble moves to the left with a velocity of 18 cm/s
i.e. ![v_1=-18\ cm/s](https://tex.z-dn.net/?f=v_1%3D-18%5C%20cm%2Fs)
considering
be the velocity of second marble after collision
The Coefficient of restitution is 1 for an elastic collision
![e=\frac{v_2-v_1}{u_1-u_2}](https://tex.z-dn.net/?f=e%3D%5Cfrac%7Bv_2-v_1%7D%7Bu_1-u_2%7D)
Putting values
![1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s](https://tex.z-dn.net/?f=1%3D%5Cfrac%7Bv_2-%28-18%29%7D%7B22.5-%28-18%29%7D%5C%5C22.5%2B18%3Dv_2%2B18%5C%5Cv_2%3D22.5%5C%20m%2Fs)
So, the velocity of the second marble is 22.5 m/s to the right after the collision
(b)Initial kinetic energy =![0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J](https://tex.z-dn.net/?f=0.5%5Ctimes%200.015%5Ctimes%20%2822.5%5Ctimes%2010%5E%7B-2%7D%29%5E2%2B0.5%5Ctimes%200.015%5Ctimes%20%2818%5Ctimes%2010%5E%7B-2%7D%29%5E2%3D6.22%5Ctimes%2010%5E%7B-4%7D%5C%20J)
Final kinetic energy=
![0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J](https://tex.z-dn.net/?f=0.5%5Ctimes%200.015%5Ctimes%20%2818%5Ctimes%2010%5E%7B-2%7D%29%5E2%2B0.5%5Ctimes%200.015%5Ctimes%20%2822.5%5Ctimes%2010%5E%7B-2%7D%29%5E2%3D6.22%5Ctimes%2010%5E%7B-4%7D%5C%20J)
Answer:
speed of molecule ∝ 1/mass of molecule.
Explanation:
The velocities of the molecules depend on their masses. That's because if the molecules are large in size, their velocity is slower. Therefore their velocity is quicker when their size is small, since the molecules can move faster.
Therefore , it can be written as
speed of molecule ∝ 1/mass of molecule.
it is important so you can discover new materials or inhabitle planets in case anything happens to earth
Answer:
The calculations is shown below on the basis of equation:
work = force × distance
Explanation:
- Here the work done is 600 J and distance is certain cm ( assume 10 cm).
- As work done is the force applied for certain distance.
Mathematically,
work = force × distance
so,
force = ![\frac{work done}{distance}](https://tex.z-dn.net/?f=%5Cfrac%7Bwork%20done%7D%7Bdistance%7D)
or, force = ![\frac{600 J}{10 cm}](https://tex.z-dn.net/?f=%5Cfrac%7B600%20J%7D%7B10%20cm%7D)
or, force= ![\frac{600J}{0.1 m}](https://tex.z-dn.net/?f=%5Cfrac%7B600J%7D%7B0.1%20m%7D)
or, force = 6000 N
or, force = 6 KN
Hence taking distance as 10 cm, the force will be 6 KN.