The question is incomplete, here is the complete question:
A sample of gas weighs 10.1 g and occupies a volume of 5.65 L at 60 °C and 580 torr. Identify the gas sample.
(a)
(molar mass = 119.4 g/mol)
(b)
(molar mass = 44.02 g/mol)
(c)
(molar mass = 64.07 g/mol)
(d)
(molar mass = 17.03 g/mol)
(e)
(molar mass = 70.90 g/mol)
<u>Answer:</u> The gas sample is
having molar mass of 64 g/mol
<u>Explanation:</u>
To calculate the molar mass of the gas, we use the equation given by ideal gas equation:
PV = nRT
Or,
![PV=\frac{w}{M}RT](https://tex.z-dn.net/?f=PV%3D%5Cfrac%7Bw%7D%7BM%7DRT)
where,
P = Pressure of the gas = 580 torr
V = Volume of the gas = 5.65 L
w = Weight of the gas = 10.1 g
M = Molar mass of gas = ?
R = Gas constant = ![62.36\text{ L. Torr }mol^{-1}K^{-1}](https://tex.z-dn.net/?f=62.36%5Ctext%7B%20L.%20Torr%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D)
T = Temperature of the gas = ![60^oC=[60+273]K=333K](https://tex.z-dn.net/?f=60%5EoC%3D%5B60%2B273%5DK%3D333K)
Putting values in above equation, we get:
![580torr\times 5.65L=\frac{10.1g}{M}\times 62.364\text{ L. torr }mol^{-1}K^{-1}\times 333K\\\\M=\frac{10.1\times 62.364\times 333}{580\times 5.65}=64g/mol](https://tex.z-dn.net/?f=580torr%5Ctimes%205.65L%3D%5Cfrac%7B10.1g%7D%7BM%7D%5Ctimes%2062.364%5Ctext%7B%20L.%20torr%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20333K%5C%5C%5C%5CM%3D%5Cfrac%7B10.1%5Ctimes%2062.364%5Ctimes%20333%7D%7B580%5Ctimes%205.65%7D%3D64g%2Fmol)
Hence, the gas sample is
having molar mass of 64 g/mol