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Amiraneli [1.4K]
4 years ago
10

The shortest distance from start to finish is called three vector addition

Physics
1 answer:
Jlenok [28]4 years ago
8 0

Answer:

False

Explanation:

The shortest distance between the starting point and the finishing point is called the Displacement. This is a vector quantity

It is obtained by subtracting the components of staring point from the components of finishing point

\overrightarrow{AB} = \overrightarrow{OB} - \overrightarrow{OA}

It can be expressed in terms of the components in three dimensional space.

Ex.

3 \overrightarrow{i} + 4 \overrightarrow{j}- 8 \overrightarrow{k}

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Jeffery gains super strength and pushes two different objects with the same amount of force. Object A accelerates at 40 m/s2, an
Montano1993 [528]

Answer: Object B

Explanation: Acceleration is directly proportional to force and inversely proportional to mass. It implies that more massive objects accelerates at a slower rate.

5 0
4 years ago
1. Which of the following is not an acceptable Physical Education activity?
Dmitrij [34]
The answer is A

Explanation:
Vacuuming doesn’t involve a lot of physical movements.
3 0
3 years ago
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a piece of metal with a mass of 15.3 grams has a temperature of 50.0°C. When the metal is placed in 80.2 grams of water at 21.0°
AleksAgata [21]

Answer:

1.21

Explanation:

Heat rise in the body happens due to heat supplied by water to the body.

Heat rise in body = m₁ c₁ ΔT₁

Where m₁ is mass of body and c₁ is its specific heat of body

Heat lost from water to the body = m₂ c₂ ΔT₂

Where m₂ is mass of water and c₂ is its specific heat of water ( c₂ =1 (since water))

Equating both:

        15.3 x c₁ x 4.3 = 80.2 x 1 x 4.3

⇒   c₁ = 80.2 / (15.3 x 4.3) = 1.21

6 0
4 years ago
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A 2.8 kg grinding wheel is in the form of a solid cylinder of radius 0.1 m. a) What constant torque will bring it from rest to a
kogti [31]

Answer:

a) τ =  0.672 N m , b) θ = 150 rad , c) W = 100.8 J

Explanation:

a) for this part let's start by finding angular acceleration, when the angular velocity stops it is zero (w = 0)

       w = w₀ + α t

       α = -w₀ / t

       α = 120 / 2.5

       α = 48 rad / s²

The moment of inertia of a cylinder is

       I = ½ M R²

Let's calculate the torque

      τ = I α

      τ = ½ M R² α

      τ = ½ 2.8 0.1² 48

      τ =  0.672 N m

b) we look for the angle by kinematics

      θ = w₀ t + ½ α t2

      θ = ½ α t²

      θ = ½ 48 2.5²

      θ = 150 rad

c) work in angular movement

      W = τ θ

      W = 0.672 150

      W = 100.8 J

7 0
3 years ago
A positive charge, q1, of 5 µC is 3 × 10–2 m west of a positive charge, q2, of 2 µC. What is the magnitude and direction of the
belka [17]
We know, F = 1/4πε * q₁q₂ / r²
Here, q₁ = 5 * 10⁻⁶ C
q₂ = 2 * 10⁻⁶ C
r = 3 * 10⁻² m west

Substitute their values, 
F = (9 * 10⁹) (5 * 10⁻⁶) (2 * 10⁻⁶)  / (3 * 10⁻²)²

F = 100 N  [ East of positive charge ]

Hope this helps!
5 0
4 years ago
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