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tia_tia [17]
3 years ago
6

Two objects with a Gravitational Force of 5000 N are moved apart 3 times the original distance. What is the new gravitational at

traction?
Physics
1 answer:
allochka39001 [22]3 years ago
6 0

Gravitational force between two objects will depends on mass and distance between the two objects

It is given by the formula as

F = \frac{Gm_1m_2}{r^2}

Now here we can say that it depends inversely on square of distance between two masses

now if force is 5000 N when two masses are at distance "r" from each other

so it is given as

5000 = \frac{Gm_1m_2}{r^2}

similarly we can say that if distance is increased by 3 times then we will have

F = \frac{Gm_1m_2}{(3r)^2}

now we will find the ratio of two forces

\frac{F}{5000} = \frac{1}{9}

so now the new force will be given as

F = \frac{5000}{9} = 555.5 N

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A car is traveling at a constant speed of 12m/s , when the driver accelerates the car reaches a speed of 26 m/s in 6s what is th
DaniilM [7]

Acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) - (start speed)

Change in speed = (26 m/s) - (12 m/s) = 14 m/s

Time for the change = 6 s

Acceleration = (14 m/s) / (6 s)

Acceleration = (14/6) (m/s²)

<em>Acceleration = 2.33 m/s²</em>

7 0
4 years ago
A mass M suspended by a spring with force constant k has aperiod T when set into oscillations on Earth. Its period on Mars,whose
olchik [2.2K]

Answer:

C)T

Explanation:

The period of a mass-spring system is:

T=2\pi\sqrt\frac{m}{k}

As can be seen, the period of this simple harmonic motion, does not depend at all on the gravitational acceleration (g), neither the mass nor the spring constant depends on this value.

6 0
4 years ago
A rock is thrown straight up into the air with an initial speed of 55 m/s at time t = 0. Ignore air resistance in this problem.
Alekssandra [29.7K]

Answer:

After 1.938 sec velocity of rock will be 36 m/sec

Explanation:

We have given initial velocity at which rock is thrown u = 55 m/sec

Final velocity v = 36 m/sec

Acceleration due to gravity g=9.8m/sec^2

According to first equation of motion we know that v=u+gt, here v is final velocity, u is initial velocity, g is acceleration due to gravity and t is time

So 36=55-9.8t ( Negative sign is due to rock is thrown upward )

So 9.8t=19

t = 1.938 sec

So after 1.938 sec velocity of rock will be 36 m/sec

8 0
4 years ago
A wire coil inside a generator has 150 square loops and an area equal to 0.042 m2.
Anna [14]

D. The maximum electromotive force induced in the coil is determined as 3,200 V.

<h3>Maximum electromotive force induced in the coil</h3>

emf(max) = NAB/t

where;

  • N is number of turns
  • B is magnetic field
  • A is area of the coil
  • t is time

Substitute the given parameters and solve for emf

emf(max) = (150 x 0.042 x 0.86) / (1.7 x 10⁻³)

emf(max) = 3,187.1 V

emf(max) ≈ 3,200 V

Thus, the maximum electromotive force induced in the coil is determined as 3,200 V.

Learn more about emf here: brainly.com/question/24158806

#SPJ1

3 0
2 years ago
Urgent!!!
Luba_88 [7]

<u>T</u><u>he area w</u><u>h</u><u>ich touches the sand floor of 4 feet of the bull is less than the man.</u>

because the area of surface of contact is more in bull than in man. More is the area of contact, leads is the force or pressure affected.

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3 years ago
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