Answer:
Explanation:
https://www.pole-barn.info/roof-rafter-calculations.html
Answer:
a) the COP of this air conditioner is 2.38
b) the rate of heat transfer to the outside air is 1065 kJ/min
Explanation:
Given the data in the question;
[ Outdoor ] ← Q [ W ] Q ← [ House ]
Rate of heat removed from the house; Q = 750 kJ/min = ( 750 kJ/min × ( 1 kW / 60 kJ/min ) ) = 12.5 kW
Net-work input; W = 5.25 kW
a) The coefficient of performance of the air conditioner; COP.
COP = Q / W
we substitute
COP = 12.5 kW / 5.25 kW
COP = 2.38
Therefore, the COP of this air conditioner is 2.38
b) the rate of heat transfer to the outside air.
Q = Q + W
we substitute
Q = 12.5 kW + 5.25 kW
Q = 17.75 kW
Q = ( 17.75 × 60 ) kJ/min
Q = 1065 kJ/min
Therefore, the rate of heat transfer to the outside air is 1065 kJ/min
Answer:
I don't understand the language French sorry can't answer
Answer:
- def processString(sentence):
- middle = len(sentence) // 2
- output = sentence[0: middle - 5] + sentence[middle+5:]
- return output
-
- print(processString("I have a dream"))
Explanation:
Create a function processString that take sentence as input paratemer (Line 1).
Next create a variable middle to hold the value of middle index of sentence string (Line 2)
Build the output string by slicing the input sentence from first character to character middle - 5th and from middle + 5th till the end of the string (Line 3).
Test the function using a sample sentence and we shall get the output "I am"
Answer:
Net discharge per hour will be 3.5325
Explanation:
We have given internal diameter d = 25 mm
Time = 1 hour = 3600 sec
So radius
We know that area is given by
We know that discharge is given by , here A is area and V is velocity
So
So net discharge in 1 hour =