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3 years ago

Reflection is the bouncing of light rays off of a surface. Which situation is NOT an example of reflection?

Physics

2 answers:

galina1969 [7]3 years ago

7 0

Answer: b.focusing light through a camera lens

Explanation:

Reflection is an optical phenomenon in which light bounces off an opaque surface on which it falls.

A mirror is formed of glass which has highly lustrous metal coated at the back. The light bounces of the surface. The image forms behind the mirror. The image is formed at the same distance as object and of the same height.

A still lake also acts as a mirror. Thus, reflection takes place from its surface and the image can be seen.

We are able to see objects when light from some source bounces off it and reaches our eye. Thus, reflection occurs here.

But, in case of camera lens, the light passes through a converging lens focuses at a point. Here, the phenomenon of refraction occurs not reflection.

marin [14]3 years ago

3 0

The answer is B. I just took the test.

I hope this helps. :)

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Hatshy [7]

The last one is correct (D)

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2 years ago

Two groups of students were tested to compare their speed working math problems,Each group was given the same problems.One group

Zanzabum

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3 years ago

Find the sum 5.24 g, 43.261 g, and 7.3458 g. Write your answer with the correct amount of significant figures.

lapo4ka [179]

Answer:

This is how I do it:

5.24 rounded to one significant figure is 5
43.261 rounded to one significant figure is 40.
7.3458 rounded to one significant figure is 7.
5 + 40 + 7 is 52 g

Hope this helps you.

Explanation:

7 0

2 years ago

A copper wire 1.0 meter long and with a mass of .0014 kilograms per meter vibrates in two segments when under a tension of 27 Ne

Furkat [3]

Answer:

the frequency of this mode of vibration is 138.87 Hz

Explanation:

Given;

length of the copper wire, L = 1 m

mass per unit length of the copper wire, μ = 0.0014 kg/m

tension on the wire, T = 27 N

number of segments, n = 2

The frequency of this mode of vibration is calculated as;

$F_n = \frac{n}{2L} \sqrt{\frac{T}{\mu} } \\\\F_2 = \frac{2}{2\times 1} \sqrt{\frac{27}{0.0014} }\\\\F_2 = 138.87 \ Hz$

Therefore, the frequency of this mode of vibration is 138.87 Hz

7 0

3 years ago

in an automobile crash, a vehicle that was stopped at a red light is rear-ended by another vehicle. The vehicles have the same m

baherus [9]

The initial speed of the vehicle before the collision is 8 m/s.

Let the mass of the vehicle = m
Let the initial speed of the vehicle stopped = u
The initial speed of the vehicle parked at the red light = 0

<h3>Principle of conservation of linear momentum</h3>

The initial speed of the vehicle before the collision is calculated by applying principle of conservation of linear momentum as follows;

$m_1 u_1 + m_2 u_2 = v(m_1 + m_2)\\\\mu + m(0) = 4(m+ m)\\\\mu = 4(2m)\\\\mu = 8m\\\\u = 8 \ m/s$

Thus, the initial speed of the vehicle before the collision is 8 m/s.

Learn more about inelastic collision here: brainly.com/question/7694106

6 0

2 years ago