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3 years ago

Reflection is the bouncing of light rays off of a surface. Which situation is NOT an example of reflection?

Physics

2 answers:

galina1969 [7]3 years ago

7 0

Answer: b.focusing light through a camera lens

Explanation:

Reflection is an optical phenomenon in which light bounces off an opaque surface on which it falls.

A mirror is formed of glass which has highly lustrous metal coated at the back. The light bounces of the surface. The image forms behind the mirror. The image is formed at the same distance as object and of the same height.

A still lake also acts as a mirror. Thus, reflection takes place from its surface and the image can be seen.

We are able to see objects when light from some source bounces off it and reaches our eye. Thus, reflection occurs here.

But, in case of camera lens, the light passes through a converging lens focuses at a point. Here, the phenomenon of refraction occurs not reflection.

marin [14]3 years ago

3 0

The answer is B. I just took the test.

I hope this helps. :)

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mixer [17]

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2 years ago

Read 2 more answers

Calculate the translational speed of a cylinder when it reaches the foot of an incline 7.05 mm high. Assume it starts from rest

mestny [16]

Height is 7.05 m and not 7.05 mm

Answer:

9.603 m/s

Explanation:

We are dealing with rotation, so velocity of centre of mass is given by;

v_cm = Rω

Since we are working with a solid cylinder, moment of inertia of the cylinder is; I = ½mR²

Since it is rolled from the top to the bottom, at the top it will have potential energy(mgh) while at the bottom it will have kinetic energy (rotational plus translational kinetic energy).

Using conservation of energy, we have:

P.E = K.E_t + K.E_r

Formula for rotational and kinetic energy here are;

K.E_t = ½mv²

K.E_r = ½Iω²

mgh = ½mv² + ½Iω²

Since we want to find translational speed(v), let's get rid of ω.

Earlier, we saw that v_cm = Rω

Thus; ω = v/R

Also, we know that I = ½mR².

Thus;

mgh = ½mv² + ½(½mR²)(v/R)²

This gives;

mgh = ½mv² + ¼mv²

Divide through by m to get;

gh = v²(½ + ¼)

gh = ¾v²

Making v the subject gives;

v = √(4gh/3)

v = √((4 × 9.81 × 7.05)/3)

v = 9.603 m/s

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2 years ago

A playground slide is in the form of an arc of a circle with a maximum height of 3.0 m, with a radius of 8.5 m, and with the gro

julia-pushkina [17]

Answer:

a) $s \approx 6.676\,m$

Explanation:

a) Let assume that the ground is not inclined, since the bottom of the playground slide is tangent to ground. Then, the length of given by the definition of a circular arc:

$s = \frac{\pi}{4}\cdot R$

$s=\frac{\pi}{4}\cdot (8.5\,m)$

$s \approx 6.676\,m$

The bottom of the slide has a height of zero. The physical phenomenon around Dr. Ritchey's daughter is modelled after Principle of Energy Conservation. The child begins at rest:

$U_{g,A} = K_{B} + W_{fr}$