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jeyben [28]
4 years ago
6

If a car traveling 85.0 kilometers per hour how many feet will it travel in 5.00 seconds

Chemistry
1 answer:
Maslowich4 years ago
4 0

The car will travel 387 ft in 5.00 s.

No. of kilometres = 5.00 s × (1 min/60 s) × (1 h/60 min) × (85.0 km/h) = 0.1181 km

No of feet = 0.1181 km × (1 mi/1.609 km) × (5280 ft/1 mi) = 387 ft


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The maximum allowable concentration of pb2+ ions in drinking water is 0.05 ppm (i.e., 0.05 g of pb2+ in 1 million grams of water
trasher [3.6K]
PbSO₄ partially dissociates in water. the balanced equation is;
                    
                       PbSO₄(s) ⇄  Pb²⁺(aq) + SO₄²⁻(aq)
Initial                                     -                -
Change             -X               +X           +X
Equilibrium                           X              X

Ksp           =    [Pb²⁺(aq)] [SO₄²⁻(aq)]
1.6 x 10⁻⁸  =    X * X
1.6 x 10⁻⁸  =    X²
          X    =   1.3 x 10⁻⁴ M
      
Hence the Pb²⁺ concentration in underground water is 1.3 x 10⁻⁴ M. 
[Pb²⁺]  = 1.3 x 10⁻⁴ M.
           = 1.3 x 10⁻⁴ mol / L x 207 g / mol 
           = 26.91 ppm

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