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4 years ago

Why can scientists ignore the gravitational force when studying the physics of an atom?

Physics

2 answers:

Nataliya [291]4 years ago

8 0

Answer:

Scientists can ignore the gravitational force because the electrical force between protons and electrons in the atom is millions of times stronger than the gravitational force between the protons and electrons. The gravitational force is insignificant for masses as small as the proton and electron.

Explanation:

frozen [14]4 years ago

7 0

The short answer is that gravitational force is so small compared to other forces (such as the attractions/repulsion between charged particles) that gravity is negligible.

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What effect does atmospheric pressure have on density?

Ivanshal [37]

Answer:sometimes it commits to how it will happen

Explanation:

4 0

3 years ago

Read 2 more answers

In a mattress test, you drop a 7.0 kg bowling ball from a height of 1.5 m above a mattress, which as a result compresses 15 cm a

Assoli18 [71]

Answer:

(d) 113.19 J

(e) 113.19 J

(f) 10061 N/m

Explanation:

15 cm = 0.15 m

Let g = 9.8 m/s2

$E_p = mgx = 7*9.8*0.15 = 10.29 J$

(d) By using law of energy conservation with potential energy reference being 0 at the maximum compression point. As the ball falls and come to a stop at the compression point, its potential energy is transferred to elastic energy, which is the work that the mattress does on the ball:

$E_p = E_e$

$E_e = mgh$

where h = 1.5 + 0.15 = 1.65 m is the vertical distance that it falls.

$E_e = 7*9.8*1.65 = 113.19 J$

(e) Before the compression, the potential energy of the mattress is 0. After the compression, the potential energy is 113.19J. So it has increased by 113.19J due to the potential energy transferred from the falling ball.

(f) $E_e = 113.19 = kx^2/2$

$k0.15^2/2 = 113.19$

$k = 10061 N/m$

8 0

3 years ago

Read 2 more answers

A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, th

Svet_ta [14]

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

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3 years ago

A car moving at some speed hits the brakes and skids to a stop after 13 m on a level road. If the coefficient of friction for th

vesna_86 [32]

Answer:

12.974 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s²

$\mu$ = Coefficient of friction =0.66

a = Acceleration = $\mu g$

$v^2-u^2=2as\\\Rightarrow -u^2=2\mu gs-v^2\\\Rightarrow u=\sqrt{v^2-2\mu gs}\\\Rightarrow u=\sqrt{0^2-2\times -(9.81\times 0.66)\times 13}\\\Rightarrow u=12.974\ m/s$