Answer:
The baseball was falling during 1.733 seconds.
Explanation:
The baseball experimented a free fall, which is a particular case of uniformly accelerated motion, in which object is accelerated by gravity. In this case, we need to determine the time spent by the ball before hitting the ground (), measured in seconds, which is determined by the following kinematic formula:
(1)
Where:
, - Initial and final speeds of the baseball, measured in meters per second.
- Gravitational acceleration, measured in meters per square second.
If we know that , and , then the time spent by the baseball is:
The baseball was falling during 1.733 seconds.
The resultant force of both forces is 15.62 N.
<h3 /><h3>What is resultant?</h3>
The Resultant of forces is a single force obtained when two or more forces are combined.
To calculate the resultant of the force, we use the formula below.
Formula:
- R = √[a²+b²-2abcos∅]..................... Equation 1
Where:
- R = Resultant of the forces.
- ∅ = Angle between both forces
From the question,
Given:
Substitute these values into equation 1
- R = √[8²+10²-2×8×10cos120°]
- R = √[64+100-160cos120°]
- R =√ [164-160(-0.5)]
- R = √[164+80]
- R = √(244)
- R = 15.62 N
Hence, the resultant force of both forces is 15.62 N.
Learn more about resultant force here: brainly.com/question/25239010
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Answer:
22510.8J
Explanation:
Given parameters:
Mass of lead = 4.68kg
Initial temperature = 25°C
Final temperature = 62°C
Unknown:
The heat needed to cause this temperature change = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the quantity of heat
m is the mass
c is the specific heat capacity
Ф is the temperature change
So;
Specific heat capacity of lead = 130J/kg°C
Insert the parameters and solve;
H = 4.68 x 130 x (62 - 25) = 22510.8J
in case you dont want to read the answer is B
The net force acting on test charge is resultant of two force i.e., √2 F
The magnitude of force on test charge due to one charge Q is:
F = k qQ / r²
where k = 9 × 10^9
Similarly the force due to second charge will be:
F = k qQ / r²
Now both the charges of magnitude Q is present and it is pointed at right angle to each other then the force will be resultant i.e.,
F = √ F² + F² = F√2
Hence, net force acting on test charge is √2 F.
Learn more about charges here:
brainly.com/question/15840431
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