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natali 33 [55]
3 years ago
8

Potential energy can transform into kinetic energy and vice versa so the total energy stay the same (reflect on the skateboard s

imulation)
A) True
B) False
Physics
1 answer:
marysya [2.9K]3 years ago
5 0
I think it’s true, but I’m not quite sure
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A string is wrapped around a pulley with a radius of 2.0 cm. The pulley is initially at rest. A constant force of 50 N is applie
Ray Of Light [21]

Answer:

0.20kg-m^2

Explanation:

Let the linear velocity of the rope(=of pulley) is v m/s

Using kinematic equation

=> v = u + at

=>v = 0 + 4.9a

=>v = 4.9a ------------ eq1

By v^2 = u^2 + 2as

=>v^2 = 0 + 2 x v/4.9 x 1.2

=>4.9v^2 - 2.4v = 0

=>v(4.9v - 2.4) = 0

=>v = 2.4/4.9 = 0.49 m/s

Thus by v = r x omega

=>omega = v/r = 0.49/0.02 = 24.49 rad/sec

BY W = F x s = 50 x 1.2 = 60 J

=>KE(rotational) = W = 1/2 x I x omega^2

=>60 = 1/2 x I x (24.49)^2

=>I = 0.20 kg-m^2

5 0
3 years ago
There is the more role of the moon than the sun to occur tides in the oceans,why?
Nana76 [90]

Answer:

The ocean tides on earth are caused by both the moon's gravity and the sun's gravity. ... Even though the sun is much more massive and therefore has stronger overall gravity than the moon, the moon is closer to the earth so that its gravitational gradient is stronger than that of the sun.

8 0
2 years ago
Light rays travel from one medium into another and refract away from the boundary. What changes about the light to cause this re
vaieri [72.5K]

Answer:

a

Explanation:

I think its a its speed increases.....

8 0
3 years ago
Read 2 more answers
How long does it take a glass of salt water to freeze than a glass of fresh water
max2010maxim [7]
A glass of salt water will take a slightly longer time & slightly lower temperature (28 F as compared to 32 F for fresh water)  to freeze than a glass of fresh water. 

Hope this helps!
6 0
3 years ago
How much thermal energy is required to raise the temperature of 5 kg of water 50℃? The specific heat of water is 4168 J/kg*C.
sasho [114]

Answer/solution:

Given :

Mass =5kg

T 1 =20 C,T 2  =100 ∘C

ΔT=100−20=80 ∘C

Q=m×C×ΔT

where C= specific heat capacity of water

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

3 0
2 years ago
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