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11Alexandr11 [23.1K]
3 years ago
5

What would be an appropriate way to display the results of the experiment outlined?

Chemistry
2 answers:
miv72 [106K]3 years ago
6 0
The best way (in my opinion) is to put it in a table or spreadsheet. 
Elodia [21]3 years ago
3 0

Answer:

Use a table or spreasheet

Explanation:

This will depend of what kind of experiment you are doing, but in general terms, you can use a table or spreadsheet to display the results of any experiment.

Let's do an example, with a simple experiment. Let's suppose we are doing an experiment to determine the density of some objects, For this, we are going to use a rock, a ball and a little box.

The experiment states that in order to determine the density, you need to weight the objects, then calculate the volume, and finally calculate the density with the expression:

d = m/V

Now, let's suppose that you weight the 3 objects, and the values are:

rock: 150 g

ball: 300 g

box: 200 g

The volume for them are:

rock: 35 cm³

Ball: 45 cm³

Box: 64 cm³

Finally the density:

rock: 4.3 g/cm³

ball: 6.7 g/cm³

box: 3.1 g/cm³

These data, will be better understandable if you write a table like the one in picture 1. In that way, you show the data you have and the results of that experiment in a better way:

Download xlsx
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The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50∘c is 2000 m/s. Note that 1. 0 mol of diatomic hydrogen at
Leno4ka [110]

The rms speed will be 500 m/s

<h3>What is Root mean square speed ?</h3>

Root mean square speed (Vrms) is defined as the square root of the mean of the square of speeds of all molecules.

Root mean square speed (vrms) Root mean square speed (vrms) is defined as the square root of the mean of the square of speeds of all molecules

It is given that

Speed of a diatomic hydrogen molecule,2000 m/s

Mol of diatomic hydrogen,1.0

Temperature,50°C

The rms speed of diatomic molecule will be:

√(3KT)/( m)

The translational kinetic energy of a gas molecule is given as:

K.E = (3/2)KT

K.E = (1/2) mv²

where,

v = root mean square velocity

m = mass of one mole of a gas

(3/2)KT = (1/2) mv²

v = √(3KT)/m  

FOR H₂:  v = √(3KT)/m = 2000 m/s  

Here,

mass of 1 mole of oxygen = 16 m

velocity of oxygen = √(3KT)/(16 m)

velocity of oxygen = (1/4) √(3KT)/m

velocity of oxygen = (1/4)(2000 m/s) = 500 m/s

Therefore the  rms (root-mean-square) speed of a oxygen molecule at 50∘c is 500m/s.

To know more about Root mean square speed

brainly.com/question/7213287

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3 0
2 years ago
How do the densities of the two objects compare?
Marizza181 [45]
Compare the density of the object in question to the density of water. If its density is less than water, it will float. For example, oak floats because its density is 0.7 g/cm³. If the density of an object is greater than water, it will sink.
3 0
3 years ago
Which action by the British government was
Lera25 [3.4K]
The answer is (4) taxing the colonies without representation in Parliament

This set off the Revolutionary War, and the slogan "no taxation without representation" became famous.
3 0
4 years ago
A chemistry student weighs out 0.027 kg of an unknown solid compound X and adds it to 550. mL of distilled water at 30.° C. Afte
QveST [7]

Answer:

1. Yes

2.The solubility of X is 34.55g/L

Explanation:

Solubility of  solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm^{3} or 1 Litre of water.

From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved

= 0.019kg*1000 = 19g.

if 19g is required to saturate 550mL at 30°C,

then\frac{19*1000}{550} will saturate 1L

= 34.545g  will saturate 1Litre

The solubility thus is 34.55g/L

 

5 0
3 years ago
A gas container has a volume of 446.9 with a temp of 14c. When the volume is decreased to 238.7l the new temp is what
swat32

Answer:

\frac{V _{1}}{T _{1}}  =  \frac{V _{2}}{T _{2} }  \\  \frac{446.9}{(14 + 273)}  =  \frac{238.7}{T _{2} } \\ {T _{2}} =  \frac{238.7 \times 287}{446.9}  \\ {T _{2}} = 153.3 \: kelvin \\  = 119.7  \degree \: c

7 0
3 years ago
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