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11Alexandr11 [23.1K]
3 years ago
5

What would be an appropriate way to display the results of the experiment outlined?

Chemistry
2 answers:
miv72 [106K]3 years ago
6 0
The best way (in my opinion) is to put it in a table or spreadsheet. 
Elodia [21]3 years ago
3 0

Answer:

Use a table or spreasheet

Explanation:

This will depend of what kind of experiment you are doing, but in general terms, you can use a table or spreadsheet to display the results of any experiment.

Let's do an example, with a simple experiment. Let's suppose we are doing an experiment to determine the density of some objects, For this, we are going to use a rock, a ball and a little box.

The experiment states that in order to determine the density, you need to weight the objects, then calculate the volume, and finally calculate the density with the expression:

d = m/V

Now, let's suppose that you weight the 3 objects, and the values are:

rock: 150 g

ball: 300 g

box: 200 g

The volume for them are:

rock: 35 cm³

Ball: 45 cm³

Box: 64 cm³

Finally the density:

rock: 4.3 g/cm³

ball: 6.7 g/cm³

box: 3.1 g/cm³

These data, will be better understandable if you write a table like the one in picture 1. In that way, you show the data you have and the results of that experiment in a better way:

Download xlsx
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Can someone please answer this?
Amanda [17]

Answer:-

0.229 L

Explanation:-

Molar mass of AgBr = 107.87 x 1 + 79.9 x 1

=187.77 grams mol-1

Mass of AgBr = 150 grams

Number of moles of AgBr = 150 grams / 187.77 gram mol-1

= 0.8 mol

The balanced chemical equation is

NaBr (aq) + AgNO3 (aq)--> AgBr(s) + NaNO3(aq)

From the equation we can see that

1 mol of AgBr is produced from 1 mol of AgNO3.

∴ 0.8 mol of AgBr is produced from 1 x 0.8 / 1 = 0.8 mol of AgNO3.

Strength of AgNO3 = 3.5 M

Volume of AgNO3 required = Number of moles / strength

= 0.8 moles / 3.5

=0.229 L

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Some chemical changes can be reactive through another chemical change?
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Igoryamba

answer:

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irga5000 [103]

Answer:

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Explanation:

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