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11Alexandr11 [23.1K]
2 years ago
5

What would be an appropriate way to display the results of the experiment outlined?

Chemistry
2 answers:
miv72 [106K]2 years ago
6 0
The best way (in my opinion) is to put it in a table or spreadsheet. 
Elodia [21]2 years ago
3 0

Answer:

Use a table or spreasheet

Explanation:

This will depend of what kind of experiment you are doing, but in general terms, you can use a table or spreadsheet to display the results of any experiment.

Let's do an example, with a simple experiment. Let's suppose we are doing an experiment to determine the density of some objects, For this, we are going to use a rock, a ball and a little box.

The experiment states that in order to determine the density, you need to weight the objects, then calculate the volume, and finally calculate the density with the expression:

d = m/V

Now, let's suppose that you weight the 3 objects, and the values are:

rock: 150 g

ball: 300 g

box: 200 g

The volume for them are:

rock: 35 cm³

Ball: 45 cm³

Box: 64 cm³

Finally the density:

rock: 4.3 g/cm³

ball: 6.7 g/cm³

box: 3.1 g/cm³

These data, will be better understandable if you write a table like the one in picture 1. In that way, you show the data you have and the results of that experiment in a better way:

Download xlsx
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the results of an investigation thank me later

Explanation:

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which of the following elements are in this unbalanced chemical reaction: li(s) + H2O(l) lioh(aq)+h2(g)​
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Answer:

Li and H

Explanation:

2Li(s)+2H2O(i)→2LiOH(aq)+H2(g) is full balanced

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2 years ago
What is the molarity of a solution of sulfuric acid if 49.0 mL of it are neutralized by a titration
vaieri [72.5K]

Answer:

THE MOLARITY OF THE ACID IS 0.232M

Explanation:

Molarity is the number of moles of solute per liter of a solution.

In titration, the molarity of the acid and the molarity of the base are related by this equation:

Ca VA / CbVb = na / nb

Ca = concentration of the acid = ?

Va = volume of the acid = 49 mL

Cb = concentration of the base = 0.333M

Vb = volume of the base = 68.4mL

Na = number of mole of acid = 1

Nb = number of mole of base = 2

Equation for the reaction:

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Solving for the molarity of the acid, we have :

Ca = CbVbNa / VaNb

Ca = 0.333M * 68.4mL * 1 / 49mL *2

Ca = 22.7772 * 10^-3 / 98 *10^-3

Ca = 0.232M

The molarity of the acid is therefore 0.232M.

8 0
3 years ago
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