Question

The total electric flux through a closed cylindrical (length = 1.2 m, diameter = 0.20 m) surface is equal to –5.0 N ⋅ m2/C. Determine the net charge within the cylinder.

Answer 1

Answer:

The net charge within the cylinder is (-44.25 pC)

Explanation:

Given that,

Total electric flux, $\phi=-5\ N-m^2/C$

Length of the cylinder, l = 1.2 m

Diameter of the cylinder, d = 0.2 m              

We know that the Gauss's law of electrostatics gives the relation between electric flux and the net charge. It is given by :

$\phi=\dfrac{q}{\epsilon_o}$

q is net charge within the cylinder

$q=\phi\times \epsilon_o\\\\q=-5\times 8.85\times 10^{-12}\\\\q=-44.25\times 10^{-12}\ C\\\\q=-44.25\ pC$

So, the net charge within the cylinder is (-44.25 pC). Hence, this is the required solution.