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3 years ago

CO

Physics

1 answer:

krek1111 [17]3 years ago

5 0

Answer:0.12 amperes

Explanation:

voltage=17.6v

Resistance=165.5 ohms

Current=voltage ➗ resistance

Current=17.6 ➗ 165.5

Current=0.12 amperes

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A rigid massless rod is rotated about one end in a horizontal circle. There is a particle of mass m1 attached to the center of t

Rzqust [24]

Answer:

m₁/m₂ =8

Explanation:

Writing the centripetal force equation: where T₁ is inner tension and T₂ is outer tension

T₂ = m₂ × ω²R....equation 1

T₁-T₂ = m₁ × ω²R/2

Also T₁=5T₂

5T₂-T₂ = m₁ × ω²R/2

4 × 2T₂ = m₁ × ω²R

8T₂ = m₁ × ω²R

dividing it by equation 1

8 = m₁/m₂

Hence m₁/m₂ =8

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3 years ago

A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The

Goshia [24]

Answer:

$0.629\ \text{rad/s}^2$ counterclockwise

$9.98\ \text{s}$

Explanation:

$r_1$ = Small drive wheel radius = 2.2 cm

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$r_2$ = Radius of pottery wheel = 28 cm

$\alpha_2$ = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

$r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2$

The angular acceleration of the pottery wheel is $0.629\ \text{rad/s}^2$ .

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

$\omega_i$ = Initial angular velocity = 0

$\omega_f$ = Final angular velocity = $60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}$

t = Time taken

From the kinematic equations of linear motion we have

$\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}$

The time it takes the pottery wheel to reach the required speed is $9.98\ \text{s}$

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3 years ago

The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt

drek231 [11]

Answer:

5 mm

Explanation:

Youngs's modulus (Y) is described by the following expression:

$Y=\frac{F*L}{\Delta L*A}$

Where F is the force exerted on the tendon, L is its length, A is its area and ΔL is its change in length (stretching).

The force in this case is 8 times the weight of the runner:

$F= 8*m*g\\F= 8*70*9.8\\F=5488 N$

Therefore, the change in length of the tendon is given by:

$\Delta L=\frac{F*L}{Y*A}\\\Delta L=\frac{5488*0.15}{0.15*10^{10}*1.1*10^{-4}}\\\Delta L= 0.004989 m$

the runner's Achilles tendon will stretch by 0.004989 m, which is roughly 5 mm.

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4 years ago

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