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Natalija [7]
3 years ago
6

Following Newton's Third Law, when a cannon goes off the cannon ball exerts a force on the cannon and the cannon exerts the same

force back on the cannon ball. Why does the cannon ball travel severl hunder feet while the cannon itself only moves a few inches?
Question 5 options:

Because the mass of the cannon ball is much less than the cannon

Because the cannon is so much larger in size than the cannon ball

Because the cannon ball is more aerodynamic than the cannon

Because the forces were not really equal
Physics
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer:

  • <u>First choice:</u><u><em> Because the mass of the cannon ball is much less than the cannon</em></u>

Explanation:

Indeed, <em>Newton's Third Law</em>, i.e. the action-reaction law, states that any action (force) will have a reaction (force) of same magnitude but opposite direction.

That means that when a cannon goes off the cannon ball exerts a force on the cannon and the cannon exerts the same force back on the cannon ball.

To find out how much the cannon ball and the cannon itsel move, you must consider Newton's second law.

  • F = m×a (force equal mass times acceleration).

Clearing the acceleration you get:

  • a = F / m

Then, since the mass is in the denominator and both the force that the cannon ball exerts on the cannon and the cannon exerts on the cannon ball are equal in magnitude, then the body that has the smaller mass (the cannon ball)  will experience a greater acceleration, which is stated by the first choice: because the mass of the cannon ball is much less than the cannon.

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attribute is defined as a quality or characteristic of a person, place, or thing

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The process of digestion breaks down proteins into smaller molecules that are used to rebuild other proteins. During digestion, proteins undergo chemical changes.

<u>Option: D</u>

<u>Explanation:</u>

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7 0
4 years ago
A box is placed on a conveyor belt that moves with a constant speed of 1.05 m/s. The coefficient of kinetic friction between the
sveticcg [70]

Answer:

The box stops in 0.139 seconds, after moving 7.29cm (0.0729m) backwards relative to the belt.

Explanation:

As the box is initially at rest relative to the earth, it is moving backwards with a speed of 1.05m/s relative to the belt. Then, the frictional force acts on the box to make it stop relative to the belt. So, we first have to write the equations of motion of the box in each axis:

x: f_k=ma\implies a=\frac{f_k}{m} \\\\y: N-mg=0\implies N=mg

Since the frictional force f_k is equal to f_k=\mu_k N=\mu_k mg, then we have that the acceleration is:

a=\frac{\mu_k mg}{m}=\mu_k g

Now, from the definition of acceleration we get:

a=\frac{v-v_0}{t}\implies t=\frac{v-v_0}{a}

And, as the final velocity is zero because the box gets to a stop, we have:

t=-\frac{v_0}{a}=-\frac{v_0}{\mu_k g}

(Don't worry about the negative sign. It will disappear because the initial velocity is also negative, since we take the box initially moving backwards)

Then, plugging in the given values, we calculate the time:

t=-\frac{(-1.05m/s)}{0.770(9.81m/s^{2})}=0.139s

In words, the time the box takes to stop sliding relative to the belt is 0.139s.

The displacement of the box in this time, is given by the kinematics formula:

v^{2}=v_0^{2}+2ax\implies x=-\frac{v_0^{2}}{2\mu_kg}

Finally, we calculate the displacement:

x=-\frac{(1.05m/s)^{2} }{2(0.770)(9.81m/s^2)}=-0.0729m=-7.29cm

This means that the box moves 7.29cm backwards relative to the belt.

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