energy extracted out of liquids an atoms are left to come closer arrange themselves shorter distance and then they solidify
Answer:
D) 11 m/s
Explanation:
The problem asks us to calculate the velocity of the hot dog with respect to the observer stationary outside the train. This velocity is given by:
![v=v_t + v_m + v_h](https://tex.z-dn.net/?f=v%3Dv_t%20%2B%20v_m%20%2B%20v_h)
where
is the velocity of the train (towards right)
is the velocity of the man (towards right)
is the velocity of the hot-dog (towards left, so we put a negative sign)
Substituting the numbers into the equation, we find
![v=+10 m/s+2 m/s-1 m/s=+11 m/s](https://tex.z-dn.net/?f=v%3D%2B10%20m%2Fs%2B2%20m%2Fs-1%20m%2Fs%3D%2B11%20m%2Fs)
and the positive sign means the velocity is toward right.
Answer:
0.22 b
Explanation:
Quadrupole moment of the nucleon is,
![Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2}](https://tex.z-dn.net/?f=Q%3D-%5Cfrac%7B2j-1%7D%7B2%28j%2B1%29%7D%5Cfrac%7B3%7D%7B5%7DR%5E%7B2%7D)
And also,
![R^{2}=R^{2} _{0}A^{\frac{2}{3} }](https://tex.z-dn.net/?f=R%5E%7B2%7D%3DR%5E%7B2%7D%20_%7B0%7DA%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
And, ![R _{0}=1.2\times 10^{-15}m](https://tex.z-dn.net/?f=R%20_%7B0%7D%3D1.2%5Ctimes%2010%5E%7B-15%7Dm)
Now,
![Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2} _{0}A^{\frac{2}{3} }](https://tex.z-dn.net/?f=Q%3D-%5Cfrac%7B2j-1%7D%7B2%28j%2B1%29%7D%5Cfrac%7B3%7D%7B5%7DR%5E%7B2%7D%20_%7B0%7DA%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D)
For Bismuth
and A is 209.
![Q=-\frac{2\frac{9}{2} -1}{2(\frac{9}{2} +1)}\frac{3}{5}(1.2\times 10^{-15}) ^{2}(209)^{\frac{2}{3} }\\Q=0.628\times 35.28\times 10^{-30} \\Q=22.15\times 10^{-30} m^{2} \\Q=0.2215\times 10^{-28} m^{2} \\Q=0.22 barn](https://tex.z-dn.net/?f=Q%3D-%5Cfrac%7B2%5Cfrac%7B9%7D%7B2%7D%20-1%7D%7B2%28%5Cfrac%7B9%7D%7B2%7D%20%2B1%29%7D%5Cfrac%7B3%7D%7B5%7D%281.2%5Ctimes%2010%5E%7B-15%7D%29%20%5E%7B2%7D%28209%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%5C%5CQ%3D0.628%5Ctimes%2035.28%5Ctimes%2010%5E%7B-30%7D%20%5C%5CQ%3D22.15%5Ctimes%2010%5E%7B-30%7D%20m%5E%7B2%7D%20%5C%5CQ%3D0.2215%5Ctimes%2010%5E%7B-28%7D%20m%5E%7B2%7D%20%5C%5CQ%3D0.22%20barn)
Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b
The answer is true about the cabins in commercial airliners that require pressurization.
<h3>Why are the cabins of commercial airplanes pressurized?</h3>
Airplanes are pressurized because the air is very thin at the high altitude where they fly. The passenger jet has a cruising altitude of about 30,000 - 40,000 feet. At this altitude or height, humans can't breathe very well and our body gets less amount of oxygen. Most aircraft cabins are pressurized to an altitude about 8,000 feet. This is called cabin altitude. Aircraft pilots have access to the control's mode of a cabin pressure control system and if needed it can command the cabin to depressurize.
So we can conclude that cabins in commercial airliners require pressurization because of the greater pressure of the surrounding environment.
Learn more about pressure here: brainly.com/question/28012687
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Answer:
the answer is 3600 kilometers