Answer:
a) μs=0.34
b) μk=0.27
Explanation:
Given that
Mass , m = 21 kg
Force required to move the block ,F= 73 N
The force required to keep the block in motion ,F ' = 58 N
Coefficient of the static friction :
The maximum value of the static friction force
fr= μs m g
At rest position
F= fr
73 = μs x 21 x 10 (take g= 10 m/s²)
μs=0.34
Therefore the Coefficient of the static friction will be 0.34.
Coefficient of the kinetic friction ;
Value of the kinetic friction force ,fr= μk m g
F' = Fr
To move the block at constant speed
58 = μs x 21 x 10 (take g= 10 m/s²)
μk=0.27
Therefore the Coefficient of the static friction will be 0.27.
Answer:
The thickness of the oil slick is
Explanation:
Given that,
Index of refraction = 1.28
Wave length = 500 nm
Order m = 1
We need to calculate the thickness of oil slick
Using formula of thickness
Where, n = Index of refraction
t = thickness
= wavelength
Put the value into the formula
Hence, The thickness of the oil slick is
The magnitude of the vector C is 96.32m
<h3>How to solve for the magnitude of vector c</h3>
Ax = AcosθA
= 40 cOS 20
= 37.59
Ay = AsinθA
-40sin20
= -13.68
Bx = B cos θ B
= 75Cos50
= 48.21
By = BsinθB
= 75sin50
= 57.45
Cx = AX + Bx
= 37.59 + 48.21
= 85.8
Cy = Ay + By
= -13.65 + 57.45
= 43.77
The magnitude is solved by
|c| =
= √85.8² + 43.77²
= 96.32m
The magnitude of the vector c is 96.32m
Read more on the magnitude of a vector here:
#SPJ1