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3 years ago

How many moles of O2 will be produced if you react 6 moles of KCIO3 ?

Chemistry

1 answer:

Romashka [77]3 years ago

4 0

9moles of O₂

Explanation:

Given parameters:

Number of moles of KClO₃ = 6moles

Unknown:

Number of moles of O₂ = ?

Solution:

KClO₃ is often known to undergo a decomposition reaction to produce KCl and O₂.

2KClO₃ → 2KCl + 3O₂

From the given equation, we know;

2 moles of KClO₃ will produce 3 mole of O₂

6 mole of KClO₃ will produce $\frac{6 x 3}{2}$ = 9moles of O₂

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

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3 years ago

at a certain pressure the density of superficial carbon dioxide is 0.469. what is the mass of a 25.0 mL sample of supercritical

Murrr4er [49]

Answer:

$\large \boxed{\text{11.7 g}}$

Explanation:

$\text{Mass} = \text{25.0 mL} \times \dfrac{\text{0.469 g}}{\text{1 mL}} = \textbf{11.7 g}\\\\\text{The mass of the carbon dioxide is $\large \boxed{\textbf{11.7 g}}$}$

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3 years ago

Drag the tiles to the correct boxes to complete the pairs.

7nadin3 [17]

The correct answer is B.

Have a great day!

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3 years ago

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compare the boiling point of water at sea leavel to the boiling point in denver (altitude = 1 mile) Explain

steposvetlana [31]

Answer:

boiling point decreases in denver

Explanation:

in higher places

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it takes less energy to bring water to the boiling point.

Less energy means less heat

which means water will boil at a lower temperature

wonderopolisorg

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2 years ago

What type of compound does the formula, CuCl2, represent? a. ionic salt b. covalent molecule

Rainbow [258]

The answer is: [B]: "ionic salt" .
___________________________________________________
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However, there is ionic bonding: Cu²⁺ and Cl⁻ ; to form: "CuCl₂" .
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3 years ago