<span> Let,
initial velocity = v m/sec,
Angle, x = 40 degrees,
horizontal-componant = v.cos(x) = 12 m/sec,
OR,
v = 12 / cos(40) = 12/0.766 = 15.67 meters/sec >================< ANSWER </span> Source(s): Fazaldin A <span> · 4 years ago </span>
<h3>
Answer: The acceleration doubles</h3>
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Explanation:
Consider a mass of 10 kg, so m = 10
Let's say we apply a net force of 20 newtons, so F = 20
The acceleration 'a' is...
F = ma
20 = 10a
20/10 = a
2 = a
a = 2
The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.
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Now let's double the net force on the object
F = 20 goes to F = 40
m = 10 stays the same
F = ma
40 = 10a
10a = 40
a = 40/10
a = 4
The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.
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In summary, if you double the net force applied to the object, then the acceleration doubles as well.
Answer:
wla na
Explanation:
hindi kasi magaling sa physic
