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kobusy [5.1K]
3 years ago
10

What type of energy is used by your body when you eat food?

Physics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

Chemical energy

Explanation:

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What is sound reverberation?
otez555 [7]
Sound reverberation is created when sound or signal is reflected.
3 0
3 years ago
State a true conclusion.
Ganezh [65]

The conclusion is; Cathy's dad has gone fishing.

<h3>What are conclusions in conditional statements?</h3>

A conditional statement is a statement with a hypothesis which is then followed by a conclusion.

A conditional statement has two parts; "if" and "then"

The hypothesis is “if,” part of a conditional statement.

The conclusion is the “then,” part of a conditional statement.

Considering the given conditional statements:

1. If it's Saturday, then Cathy's dad goes fishing.

2. If it's Saturday, then Cathy's dad goes fishing.

Since the if part is true, the conclusion will be, Cathy's dad has gone fishing.

In conclusion, a conditional statement consists of a hypothesis and a conclusion.

Learn more about conditional statements at: brainly.com/question/21170
#SPJ1

7 0
2 years ago
Can someone please help me with these physics problems? I just don’t even know where to start.
KIM [24]

#1

for the block of mass 5 kg normal force is given as

F_n = mg

F_n = 5*9.8 = 49 N

friction force is given as

F_f = \mu F_n

F_f = 0.1*49 = 4.9 N

Net force is given as

F_{net} = ma

F_{net} = 5*2 = 10 N

now we know that

F_{net} = F_{app} - F_f

10 = F_{app} - 4.9

F_{app} = 14.9 N

#2

Normal force is given as

F_n = mg

F_n = 6*9.8

F_n = 58.8 N

now we know that

F_{net} = F_{app} - F_f

F_{net} = 0

as object moves with constant velocity

F_{app} = F_f = 15 N

now for coefficient of friction we can use

F_f = \mu F_n

15 = \mu * 58.8

\mu = 0.255

#3

net force upwards is given as

F = 1.2 * 10^{-4} N

mass is given as

m = 7 * 10^{-5} kg

now as per newton's law we can say

F = ma

1.2 * 10^{-4} = 7 * 10^{-5} * a

a = 1.71 m/s^2

#4

As we know that when block is sliding on rough surface

part a)

net force = applied force - frictional force

F_{net} = F_{app} - F_f

ma = F_{app} - F_f

5*6 = 40 - F_{f}

F_f = 40 - 30 = 10 N

part b)

for coefficient of friction we can use

F_f = \mu F_n

10 = \mu * F_n

here normal force is given as

F_n = mg = 5*9.8 = 49 N

now we have

\mu = \frac{10}{49} = 0.204

#5

if an object is initially at rest and moves 20 m in 5 s

so we can use kinematics to find out the acceleration

d = v_i*t + \frac{1}{2}at^2

20 = 0 + \frac{1}{2}a(5^2)

a = 1.6 m/s^2

now net force is given as

F_{net} = ma

F_{net} = 10*1.6 = 16 N

#6

an object travelling with speed 25 m/s comes to stop in 1.5 s

so here acceleration of object is given as

a = \frac{v_f - v_i}{t}

a = \frac{0 - 25}{1.5} = -16.67 m/s^2

now the force is gievn as

F = ma

F = 5*16.67 = 83.3 N

3 0
3 years ago
What is electric force ​
AysviL [449]

Electric force occurs between positive and negative electric charge. It can be calculated with formula F=\frac{Q_1Q_2}{A\epsilon_0\epsilon_r} where F is force, Q1 and Q2 are charges, A is area of object usually ball (A=4\pi r^2) because we describe charges as points in space like electrons and protons, \epsilon_0 is a natural dielectric constant of empty space or vacuum (\epsilon_0=8.85\times10^{-12}\mathsf{\frac{As}{Vm}}) and \epsilon_r also known as relative dielectric variable.

There are two types of the force:

1. Attractive electric force

2. Repulsive electric force

Attractive electric force occurs between positively and negatively charged objects while repulsive occurs between equally charged objects for eg. (positive and positive will repulse).

8 0
3 years ago
A golfer hits a ball on a level fairway at an angle of 40o relative to the horizontal, and it lands on the green. Another golfer
topjm [15]

Answer:

θ' = 50°

Explanation:

Given:

- First ball launched with angle θ = 40 °

- The both balls land at the same spot on green

- Both balls hit with same velocity

Find:

what is the launch angle for the second golfer θ'.

Solution:

- We are given that both balls land at the same horizontal distance from initial position. So we can say that the range of projectile motion for both balls is same.

- The range of projectile motion as a function of θ is given as:

                           Range = v^2*sin (2*θ) / g

Where,  v: The initial striking velocity

             g: The gravitational acceleration.

- Since, the Ranges for both balls is same we have:

                           v^2*sin (2*θ) / g = v^2*sin (2*θ') / g

- Velocity v and g are constants and canceled out:

                              sin (2*θ) = sin (2*θ')

- Plug θ = 40° :

                              sin ( 80 ) = sin (2*θ')

                              arcsin ( sin ( 80 ) ) = 2*θ'

                              2*θ' = (80 , 180 - 80)

                              θ' = (40° , 100/2 = 50°)

- Hence, the second ball is launched with a different launch angle θ' = 50°.

               

5 0
3 years ago
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