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Lady_Fox [76]
3 years ago
5

The forced exerted on an object are shown. If the object moves right, which of the following is a possible value of F? Ignore my

answer please help.

Physics
2 answers:
Deffense [45]3 years ago
8 0

Answer:

5N

Explanation:

Because if it moves to the right, that means F is weak and 6N is STRONK

nata0808 [166]3 years ago
6 0
5N.....................
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He does whatever a spider can. Spider-Man, who has a mass of 76 [kg], is clinging onto an inclined wall forming an inclination a
Aliun [14]

Answer:570.54 N

Explanation:

Given

mass of man=76 kg

\theta =50^{\circ}

As man is standing over inclined building therefore

its weight has two components i.e. sin and cos component

Force perpendicular to inclined wall

F=mgcos\theta =76\times 9.8\times \sin 50

F=570.54 N

4 0
3 years ago
2. For a rotating rigid body, which of the following statements is NOT correct?
AfilCa [17]

Answer:

                                                dasgfwe

Explanation:

6 0
3 years ago
At the circus, a 100.-kilogram clown is fired at 15 meters per second from a 500.- kilogram cannon. What is the recoil speed of
photoshop1234 [79]

The recoil velocity of cannon is (4) 5.0 m/s

Explanation:

We can find the recoil velocity from the law of conservation of momentum.

The recoil velocity is velocity of body 2 after release of body 1, i.e. velocity of cannon after release of clown.

Let v2 be cannon's velocity, v1 be clown's velocity given = 15 m/sec

m1 be clown's mass = 100kg and m2 be cannon's mass given = 500kg.

So recoil velocity of cannon v2 is given by,

v2 = -(m1÷m2)v1

v2 = -(100÷500)15

v2 = -5 m/s

where the minus sign refers to the direction of cannon's recoil velocity being opposite to that of clown.

Hence, option (4)5.0 m/s is the correct answer.

6 0
3 years ago
Read 2 more answers
A stiff wire 32.5 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l
Flauer [41]

Answer: i personally think it would be 789

Explanation:

Hopefully I am right

4 0
3 years ago
A book is pushed with an initial horizontal velocity of 5.0 meters per second off the top of a desk. What is the initial vertica
PSYCHO15rus [73]

Answer:

The Initial vertical velocity is zero

Explanation:

Given that,

A book is pushed with an initial horizontal velocity, Vx = 5 m/s

According to projectile motion, the horizontal component of velocity i.e., in X-axis remains the same though out its path.

The vertical velocity varies i.e., the velocity towards the Y- axis.

The velocity of the falling book in its trajectory is the resultant velocity. Due to the action of gravity, it keeps on increasing with time.

The resultant velocity is given by relation

                V_{R} = \sqrt{{V_{x}^{2}} +[ {gt}]^{2} }

where

               gt = Vy - vertical velocity

                        g - acceleration due to gravity

                        t - time

Since, the initial horizontal velocity at that instant is equal to the resultant velocity.

                  Vx  = 5 m/s

                  V_{R}  = 5   m/s

So, on substituting in the above equation          

                         Vy = 0  m/s

Therefore, the initial vertical velocity is equal to zero

7 0
3 years ago
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