- K.E=18750J
- Mass=m=2100kg
- Velocity=v
1200 N-m of torque is used to drive a gear (A) of diameter 25 cm, which in turn drives another gear (B) of diameter 52 cm. What
torque is transmitted by gear B to its shaft? Give your answer in kN-m.
2 answers:
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Answer:
K.E = 0.0075 J
Explanation:
Given data:
Mass of the ball = 1.5 kg
radius, r = 50 cm = 0.5 m
Angular speed, ω = 12 rev/min = (12/60) rev/sec = 0.2 rev/sec
Now,
the kinetic energy is given as:
K.E =
where,
I is the moment of inertia = mr²
on substituting the values, we get
or
K.E = 0.0075 J