Answer:
greater acceleration is experienced by the car with lower mass
Explanation:
Since both the toys are connected by same spring so the force due to spring on both the toys will be same and it is given as

now we know by Newton's II law

so here we have

here we have same force on both the blocks
so acceleration will be more if mass is less
so greater acceleration is experienced by the car with lower mass
Incandescent light is a glowing white light produced by heat. An incandescent light bulb works by heating a filament in the bulb. Fluorescent light is a bright light produced by electricity flowing through a tube filled with ionized gas. Fluorescent light bulbs are more energy-efficient than incandescent bulbs
U=10 m/s
v=30 m/s
t=6 sec
therefore, a=(v-u)/t
=(30-10)/6
=(10/3) ms^-2
now, displacement=ut+0.5*a*t^2
=60+ 0.5*(10/3)*36
=120 m
And you can solve it in another way:
v^2=u^2+2as
or, s=(v^2-u^2)/2a
=(900-100)/6.6666666.......
=120 m