Question

Light with a wavelength of 488 nm is incident on a single slit with a width of 6.23 x 10^-4 m. If the screen is 2.7 m away, what is the distance to the first antinodal line?

Answer 1

Answer:

The distance to the first anti-nodal line is $2.11\times10^{-3}\ m$.

Explanation:

Given that,

Wavelength = 488 nm

Width $d=6.23\times10^{-4}\ m$

Distance D =2.7 m

We need to calculate the distance to the first anti-nodal line

Using formula of the distance for first anti-nodal line

$y_{n}=\dfrac{n\lambda D}{d}$.....(I)

Where, n = number of fringe

d = width

D = distance from the screen

$\lambda$=wavelength of light

Put the all value in the equation (I)

$y_{n}=\dfrac{488\times10^{-9}\times2.7}{6.23\times10^{-4}}$

$y_{n}=2.11\times10^{-3}\ m$

Hence, The distance to the first anti-nodal line is $2.11\times10^{-3}\ m$.