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riadik2000 [5.3K]
3 years ago
11

AM signals travel as changes in?

Physics
1 answer:
gtnhenbr [62]3 years ago
3 0
It definitely changes in frequency. For example if the frequency is medium the signals change after the sunset and it changes in the ionosphere cause medium frequency travels in the skywave. 
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Which statement explains the flow of heat? Heat moves from one place to another like a radiating wave. Heat moves as packets of
Kamila [148]

Answer:

C. Heat moves as molecules of one substance collide with molecules of another substance, transferring kinetic energy.

Explanation:

I tried it and got it right.

5 0
3 years ago
Please help!!!!!!!!!
Inessa [10]

A, D is the correct answers


6 0
3 years ago
Light of wavelength 519 nm passes through two slits. In the interference pattern on a screen 4.6 m away, adjacent bright fringes
Veseljchak [2.6K]

Answer:

The separation of the two slits is 0.456 mm.

Explanation:

Given the wavelength of light = 519 nm

The indifference pattern = 4.6 m

Adjacent bright fringes = 5.2 mm

In the interference, the equation required is Y = mLR/d

Here, d sin theta = mL

L = wavelgnth

For bright bands, m is the  order = 1,2,3,4  

For dark bands,  m = 1.5, 2.5, 3.5, 4.5

R = Distance from slit to screen (The indifference pattern)

Y = Distance from central spot to the nth  order fringe or fringe width

Thus,  here d = mLR/Y

d = 1× 519nm × 4.6 / 5.2mm

d = 0.459 mm

3 0
4 years ago
Epsilon Eridani is a star that is 10.5 light years away from Earth. One light year is about 9.46 trillion kilometers The distanc
motikmotik
Given the relation that 1 light year = 9.46 trillion kilometers, and the distance from Epsilon Eridani to Earth which is 10.5 light years, we can solve for the distance between the star and Earth in light years by multiplying both values together. This is shown below

Dsitance (in trillion km) = 9.46 trillion km * (10.5) = 99.33 trillion kilometers

7 0
4 years ago
A sanding disk with rotational inertia 2.0 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit
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Answer

Given,

Rotational inertia = 2.0 x 10-3 kg·m²

Torque = 11 N.m

time, t = 19 ms

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  \Delta L = \tau \Delta t

  \Delta L = 11\times 19 \times 10^{-3}

  \Delta L = 0.209\ Kg m^2/s

b) Angular velocity

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     \omega = \dfrac{L}{I}

     \omega = \dfrac{0.209}{2\times 10^{-3}}

     \omega = 104.5\ rad/s

4 0
3 years ago
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