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yan [13]
3 years ago
5

Two balls of equal mass are thrown horizontally with the same initial velocity. They hit identical stationary boxes resting on a

frictionless horizontal surface. The ball hitting box 1 bounces back, while the ball hitting box 2 gets stuck. 1)Which box ends up moving faster?
Physics
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

The box 1 moves faster.

Explanation:

lets

Mass =m  kg

Initial velocity = u m/s

Initial velocity of box = 0 m/s

Let stake mass of block = m

When ball bounces back:

The final speed of the box = v

Final speed of ball = - u

Pi = Pf  ( From linear momentum conservation)

m x u + m x 0 = m ( - u) + m v

mu + mu = m v

v= 2 u

When ball get stuck :

The final speed of ball and box = v

Pi = Pf  ( From linear momentum conservation)

m x u + m x 0 = (m+m) v

v= u /2

So the box 1 moves faster.

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kotykmax [81]

Answer:

The SI unit of thermal conductivity is watts per meter-kelvin (W/(m⋅K)).

Explanation:

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2 years ago
I need help with egg drop assignments any ideas?
Jet001 [13]

Answer:

make a parachute out of the bag connecting to a bowl made out of paper filled with cotton balls. then put the egg in the bowl.

Explanation:

7 0
2 years ago
¿Cuál es la frecuencia de una ola con una velocidad de 14 m / s y una longitud de onda de 20 metros?
Margaret [11]

Responder:

<h2>0.7Hertz </h2>

Explicación:

Usando la fórmula para calcular la velocidad de onda que se expresa como se muestra.

Velocidad de una onda = frecuencia * longitud de onda

v = fλ

Dada la velocidad de onda = 14 m / sy longitud de onda = 20 metros

frecuencia f = v / λ

f = 14/20

f = 0.7Hertz

La frecuencia de la onda es de 0.7 Hertz.

7 0
3 years ago
A car travels 2155.0m in 195.9s. What is the car's average speed?
inna [77]

Average speed of the car is 11 m/s

Explanation:

  • Speed is calculated by the rate of change of displacement.
  • It is given by the formula, Speed = Distance/Time
  • Here, distance = 2155 m and time = 195.9 s

Speed of the car = 2155/195.9 = 11 m/s

3 0
3 years ago
A bowling ball with a momentum of 18kg-m/s strikes a stationary bowling pin. After the collision, the ball has a momentum of 13k
Veronika [31]

Answer:

14.98\ \text{kg m/s}

45.26^{\circ}

Explanation:

P_1 = Initial momentum of the pin = 13 kg m/s

P_i = Initial momentum of the ball = 18 kg m/s

P_2 = Momentum of the ball after hit

55^{\circ} = Angle ball makes with the horizontal after hitting the pin

\theta = Angle the pin makes with the horizotal after getting hit by the ball

Momentum in the x direction

P_i=P_1\cos55^{\circ}+P_2\cos\theta\\\Rightarrow P_2\cos\theta=P_i-P_1\cos55^{\circ}\\\Rightarrow P_2\cos\theta=18-13\cos55^{\circ}\\\Rightarrow P_2\cos\theta=10.54\ \text{kg m/s}

Momentum in the y direction

P_1\sin55=P_2\sin\theta\\\Rightarrow P_2\sin\theta=13\sin55^{\circ}\\\Rightarrow P_2\sin\theta=10.64\ \text{kg m/s}

(P_2\cos\theta)^2+(P_2\sin\theta)^2=P_2^2\\\Rightarrow P_2=\sqrt{10.54^2+10.64^2}\\\Rightarrow P_2=14.98\ \text{kg m/s}

The pin's resultant velocity is 14.98\ \text{kg m/s}

P_2\sin\theta=10.64\\\Rightarrow \theta=sin^{-1}\dfrac{10.64}{14.98}\\\Rightarrow \theta=45.26^{\circ}

The pin's resultant direction is 45.26^{\circ} below the horizontal or to the right.

4 0
2 years ago
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