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Veseljchak [2.6K]
2 years ago
12

Two swimmers compete in a race. Under what condition do the swimmers have the same power?

Physics
2 answers:
Korvikt [17]2 years ago
6 0

When both swimmers do work at the same rate.

Plz mark brainliest.

harkovskaia [24]2 years ago
5 0

Answer:

When both swimmers do work at the same rate.    

Explanation:

It is given that two swimmers compete in a race. The rate of doing work is called the power of a swimmer. Mathematically, the power of any object can be written as :

P=\dfrac{W}{t}

Where

W is the work done

t is the time taken by the swimmer

We can say that the power depends on the at rate at which the work is done. When both the swimmers do work at the same rate, then they both have same power.

Hence, the correct option is (b).            

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Infrared telescopes are usually placed on high-flying airplanes or on satellites in space __________
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Answer:

In order to improve visibility

Explanation:

Infrared telescopes are made using infrared cameras that contain infrared detectors which are solid-state and are maintained at very cold (cryogenic) temperatures

Infrared radiation is absorbed by water vapor which is present in the Earth's atmosphere, leading to the limitation of the use of infra red telescopes at high altitudes such as mountains, high flying planes or satellites

3 0
2 years ago
When a magnet is dropped why does it lose its magnetic properties
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When a magnet is dropped, the domain become unaligned. 
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Answer: 89

Explanation:

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3 years ago
Determine a formula for the acceleration of the system in terms of mA, mB, θ, and g. Ignore the mass of the cord and pulley. Exp
jekas [21]

Answer:

a=\frac{mBg-mAgSin\theta}{mA+mB}

Explanation:

Given two mass on an incline code mA and mB and an angle of inclination \theta. g. Assume that mA is the weight being pulled up and mB the hanging weight.

-The equations of motion from Newton's Second Law are:

mBg-T=mBa where a is the acceleration.

#Substituting for T (tension) gives:

mBg-mAsin\theta-mAa=mBa

#and solving for a:

a=\frac{mBg-mAgSin\theta}{mA+mB} which is the system's acceleration.

8 0
3 years ago
A test charge of -1.4 x 10-7 coulombs experiences a force of 5.4 x 10-1 newtons. Calculate the magnitude of the electric field c
VARVARA [1.3K]

Answer:

3.86×10⁶ Newton/coulombs

Explaination:

Applying,

E = F/q....................... Equation 1

Where E = Electric Field, F  = Force, q = charge.

From the question,

Given: F = 5.4×10⁻¹ N, q = -1.4×10⁻⁷ coulombs

Substitute these values into equation 1

E = 5.4×10⁻¹/ -1.4×10⁻⁷

E = -3.86×10⁶ Newtons/coulombs

Hence the magnitude of the electric field created by the

negative test charge is 3.86×10⁶ Newton/coulombs

5 0
2 years ago
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