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cluponka [151]
3 years ago
7

What causes ocean water to become denser?

Physics
2 answers:
rosijanka [135]3 years ago
5 0

Answer:

The <u><em>SALINITY OF THE WATER AND LOWER TEMPURTURES CAUSES OCEANS WATER TO BE DENSE.....</em></u>

Explanation:

katrin2010 [14]3 years ago
3 0
The salinity of the water and lower temperatures causes ocean water to be denser.
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A launched hopper reach to 1.20 m maximum height. How much is it’s launch velocity?
garri49 [273]

The launch velocity is 4.8 m/s

Explanation:

We can solve this problem by applying the law of conservation of energy. In fact, the mechanical energy of the hopper (equal to the sum of the potential energy + the kinetic energy) is conserved. So we can write:

U_i +K_i = U_f + K_f

where:

U_i is the initial potential energy, at the bottom

K_i is the initial kinetic energy, at the bottom

U_f is the final potential energy, at the top

K_f is the final kinetic energy, at the top

We can rewrite the equation as:

mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2

where:

m is the mass of the hopper

g=9.8 m/s^2 is the acceleration of gravity

h_i = 0 is the initial height

u is the launch speed of the hopper

h_f = 1.20 m is the maximum altitude reached by the hopper

v = 0 is the final speed (which is zero when the hopper reaches the maximum height)

Solving the equation for u, we find the launch speed of the hopper:

u=\sqrt{2gh_g}=\sqrt{2(9.8)(1.20)}=4.8 m/s

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647  

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4 0
3 years ago
Sound waves that enter the external acoustic meatus eventually encounter the __________, which then vibrates at the same frequen
7nadin3 [17]

Answer:

tympanic membrane (eardrum)

Explanation:

The sound waves spread through the air and reach the outer ear, into which they penetrate through the ear canal. In doing so, they stimulate the eardrum, which closes the inner end of the duct. By vibrating this membrane, the vibration of a chain of ossicles located in the middle ear is induced. These ossicles transmit their vibration to the oval window, which is a membranous structure that communicates the middle ear with the cochlea of ​​the inner ear. When the oval membrane moves, it moves the liquid (perilymph) that fills one of the three cavities of the cochlea generating waves in it. These waves mechanically stimulate the sensory cells (hair cells) located in the organ of Corti, within the cochlea in the central cavity, the middle ramp. This cavity is filled with a liquid rich in K +, endolymph. The cells embedded in the endolymph, change their permeability to K + due to the movement of the cilia and respond by releasing a neurotransmitter that excites the nerve terminals, which initiate the auditory sensory pathway.

3 0
3 years ago
Newtons law of garvitation is known as universal law. Why​
xeze [42]

Answer:

It is called so because it is applicable on all bodies having mass, and the bodies will be governed by the same law, that is newton's law of gravitation. Thus, as it is applicable universally, it is called as universal law.

5 0
4 years ago
A circular loop in the plane of a paper lies in a 0.45 T magnetic field pointing into the paper. The loop's diameter changes fro
Amanda [17]

Answer:

(A). The direction of the induced current will be clockwise.

(B). The magnitude of the average induced emf 16.87 mV.

(C). The induced current is 6.75 mA.

Explanation:

Given that,

Magnetic field = 0.45 T

The loop's diameter changes from 17.0 cm to 6.0 cm .

Time = 0.53 sec

(A). We need to find the direction of the induced current.

Using Lenz law

If the direction of magnetic field shows into the paper then the direction of the induced current will be clockwise.

(B). We need to calculate the magnetic flux

Using formula of flux

\phi_{1}=BA\cos\theta

Put the value into the formula

\phi_{1}=0.45\times(\pi\times(8.5\times10^{-2})^2)\cos0

\phi_{1}=0.01021\ Wb

We need to calculate the magnetic flux

Using formula of flux

\phi_{2}=BA\cos\theta

Put the value into the formula

\phi_{2}=0.45\times(\pi\times(3\times10^{-2})^2)\cos0

\phi_{2}=0.00127\ Wb

We need to calculate the magnitude of the average induced emf

Using formula of emf

\epsilon=-N(\dfrac{\Delta \phi}{\Delta t})

Put the value into t5he formula

\epsilon=-1\times(\dfrac{0.00127-0.01021}{0.53})

\epsilon=0.016867\ V

\epsilon=16.87\ mV

(C). If the coil resistance is 2.5 Ω.

We need to calculate the induced current

Using formula of current

I=\dfrac{\epsilon}{R}

Put the value into the formula

I=\dfrac{0.016867}{2.5}

I=0.00675\ A

I=6.75\ mA

Hence, (A). The direction of the induced current will be clockwise.

(B). The magnitude of the average induced emf 16.87 mV.

(C). The induced current is 6.75 mA.

5 0
3 years ago
How can you describe the path of the projectile motion?
tresset_1 [31]

Answer:

Projectile motion is a form of motion where an object moves in a bilaterally symmetrical+ parabolic path.

Explanation:

5 0
3 years ago
Read 2 more answers
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