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irina1246 [14]
3 years ago
9

A coin is tossed 5 times in a row. What is the size of the sample space of this experiment?

Physics
1 answer:
olasank [31]3 years ago
5 0
The sample space of an experiment includes a set of different possibilities that can happen in the bounds of the experiment. A coin tossed once has two possibilities - heads or tails. When the coin is tossed five times, the sample space is 20: HHHHH, HHHHT, HHHTT, HHTTT, HTTTT, TTTTT, THHHH, TTHHH, TTTHH, TTTTH, THTHTH, HTHTHT, THHTT, THHHT, HTTTH, HTTHH, THHTT, etc. 
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Elements<span> in the same </span>group<span> in the periodic table </span>have similar chemical properties<span>. This is because their atoms </span>have<span> the same number of electrons in the highest occupied energy level. </span>Group<span> 1 </span>elements<span> are reactive metals called the alkali metals.</span>Group<span> 0 </span>elements<span> are unreactive non-metals called the noble gases.
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Human eyes detect only a very small band of the electromagnetic spectrum. However, some animals and insects see in higher and lo
hoa [83]

Answer:

Squids = 450 - 490 nm (Moderate Frequency) (Blue)

Bees = 300 - 650 nm (Lower Frequency Bands)

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Explanation:

All of the above mentioned ranges are compared to that of humans.

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kolbaska11 [484]
<h3>Question 1</h3>

Answer

option C) velocity

Explanation

acceleration =  Δv ÷ Δt

<h3>Question 2</h3>

Answer

option C) m/s²

Explanation

Δv ÷ Δt

= m/s ÷ s

= m/s x 1/s

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<h3>Question 3</h3>

Answer

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7 0
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Read 2 more answers
As a system expands, it absorbs 52.5 J of energy in the form of heat from the surroundings. The piston is working against a pres
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Answer:

Vi = 0.055 m³ = 55 L

Explanation:

From first Law of Thermodynamics, we know that:

ΔQ = ΔU + W

where,

ΔQ = Heat absorbed by the system = 52.5 J

ΔU = Change in Internal Energy = -102.5 J (negative sign shows decrease in internal energy of the system)

W = Work Done in Expansion by the system = ?

Therefore,

52.5 J = - 102.5 J + W

W = 52.5 J + 102.5 J

W = 155 J

Now, the work done in a constant pressure condition is given by:

W = PΔV

W = P(Vf - Vi)

where,

P = Constant Pressure = (0.5 atm)(101325 Pa/1 atm) = 50662.5 Pa

Vf = Final Volume of System = (58 L)(0.001 m³/1 L) = 0.058 m³

Vi = Initial Volume of System = ?

Therefore,

155 J = (50662.5 Pa)(0.058 m³ - Vi)

Vi = 0.058 m³ - 155 J/50662.5 Pa

Vi = 0.058 m³ - 0.003 m³

<u>Vi = 0.055 m³ = 55 L</u>

7 0
3 years ago
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Answer:

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