Can some one please help me First person to answer me wins 75 points
1 answer:
You might be interested in
<u>Answer:</u> The atomic symbol of the given element is
<u>Explanation:</u>
The general isotopic representation of an element is given as:
where,
Z represents the atomic number of the element
A represents the mass number of the element
X represents the symbol of an element
For the given isotope: 130-iodine
Mass number = 130
Atomic number = 53
Hence, the atomic symbol of the given element is
Answer:
81.3 %
Explanation:
The formula for the calculation of moles is shown below:
For ferrocene:-
Mass of ferrocene = 100 mg = 0.1 g
Molar mass of ferrocene = 186.04 g/mol
The formula for the calculation of moles is shown below:
Thus,
For acetyl chloride:-
Volume = 40 microliters = 0.04 mL
Density = 1.1 g / mL
Density is defined as:-
or,
Mass of acetyl chloride = 0.044 g
Molar mass of acetyl chloride = 78.49 g/mol
The formula for the calculation of moles is shown below:
Thus,
As per the reaction stoichiometry, one mole of ferrocene reacts with one mole of acetyl chloride to give one mole of monoacetylferrocene
Limiting reagent is the one which is present in small amount. Thus, ferrocene is limiting reagent.
The formation of the product is governed by the limiting reagent. So,
one mole of ferrocene on reaction forms one mole of monoacetylferrocene
0.0005375 mole of ferrocene on reaction forms 0.0005375 mole of monoacetylferrocene
Moles of product formed = 0.0005375 moles
Molar mass of monoacetylferrocene = 228.07 g/mole
Mass of monoacetylferrocene produced = Moles*molecular weight = 0.0005375*228.07 g = 0.123 grams = 123 mg
Given experimental yield = 100 mg
<u>% yield = (Experimental yield / Theoretical yield) × 100 = (100/ 123) × 100 = 81.3 %</u>