<span>There are 2.74603 * 10^25 hydrogen atoms. Ammonium sulfide is represented by (NH4)2S. This means that there are 8 hydrogen atoms total. There are also 8 mol of H in ammonium sulfide. We also need to use avogadro’s number of 6.022 * 10^23.
Hydrogen Atoms = 5.7mol * (8mol / 1mol) * 6.022 * 10^23 per mol
Hydrogen atoms = 2.74603 * 10^25 hydrogen atoms.</span>
Answer:
Ok, so the process here is to convert the mass of H2 (hydrogen gas) to moles by dividing the mass by the molar mass of H2. Once you have the moles then you have to multiply by the STP (standard temperature and pressure) molar volume which should be 22.4.
Molar mass of H2 = (1.01)x2 = 2.02g/mol
19.3/2.02 = 9.55 moles
Now just multiply the moles by the molar volume
9.55 moles x 22.4 = 213.92 Litres of H2 are in 19.3g of H2
The number of C atoms in 0.524 moles of C is 3.15 atoms.
The number of
molecules in 9.87 moles
is 59.43 molecules.
The moles of Fe in 1.40 x
atoms of Fe is 0.23 x 
The moles of
in 2.30x
molecules of
is 3.81.
<h3>What are moles?</h3>
A mole is defined as 6.02214076 ×
of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
A. The number of C atoms in 0.524 mole of C:
6.02214076 ×
x 0.524 mole
3.155601758 atoms =3.155 atoms
B. The number of
molecules in 9.87 moles of
:
6.02214076 ×
x 9.87
59.4385293 molecules= 59.43 molecules
C. The moles of Fe in 1.40 x
atoms of Fe:
1.40 x
÷ 6.02214076 × 
0.2324754694 x
moles.
0.23 x
moles.
D. The moles of
in 2.30x
molecules of
:
2.30x
÷ 6.02214076 × 
3.819239854 moles=3.81 moles
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Answer ; The question is missing in some details, but here are he details ;
The two naturally occurring isotopes of bromine are
81Br (80.916 amu, 49.31%) and
79Br (78.918 amu, 50.69%).
The two naturally occurring isotopes of chlorine are
37Cl (36.966 amu, 24.23%) and
35Cl (34.969 amu, 75.77%).
Bromine and chlorine combine to form bromine monochloride, BrCl.
Explanation:
The detaile calculation is as shown in the attachment.