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ExtremeBDS [4]
4 years ago
9

Photosynthesis

Chemistry
1 answer:
3241004551 [841]4 years ago
7 0
CONVERTS GLUCOSE INTO ENERGY AND WATER
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Which natural polymers are involved with making clothing?
fredd [130]

Answer:

A. wool, silkworm, cocoon, and cellulose

Explanation:

I hope this helped!

7 0
3 years ago
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Microscopic shells that are buried under the seabed are converted to organic sedimentary rocks. during this process, which prope
RideAnS [48]

the mass of the shells will remain the same because you can not change mass even if you were to leave this planet and go to the moon your weight would change but your mass remains the same

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Can you solve this science question ⁉️​
saveliy_v [14]

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chemical reaction between those a b c it's a reaction which occurs when heating

8 0
3 years ago
A graduated cylinder contains 15.75 mL of water. A metal that weighs 32.138 g is added.
dexar [7]
<span>Displaced volume:

final volume - initial volume :

38.55 mL - 15.75 mL = 22.8 mL

D = m /  V

D = 32.138 / 22.8

D = 1.409 g/mL

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5 0
3 years ago
A laser pulse with wavelength 525 nm contains 4.40 mj of energy. How many photons are in the laser pulse
Alexandra [31]

The laser pulse in this question has a wavelength of \lambda=524 nm=525\times 10^{-9}m. To solve this problem, we first have to calculate the energy of a single photon in the laser pulse. The equation for calculating the energy of a single photon of an electromagnetic wave is E=\frac{hc}{\lambda} where c is the speed of light, h is planks constant and \lambda is the wave length of the photons.

For this problem, c=3.0\times 10^8m/s, h=6.63\times10^{-34}J.s and \lambda=525\times 10^{-9}m. We use these values to calculate the energy of the photon as shown below,

E=\frac{hc}{\lambda} \\E=\frac{(6.63\times 10^{32}Js)\times(3.0\times10^8m/s)}{525\times 10^{-9}m} \\E=3.79\times 10 ^{-19}J.

Now that we know the energy for a single photon, we will divide the total energy given by the energy of one photon to get the number of photons in the pulse. The number of photons n is calculated as shown below,

n=\frac{4.4\times 10^{-3}J}{3.79\times10^{-19}J} =1.16\times 10^{16}. There are 1.16\times 10^{16} photons.

5 0
3 years ago
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