Well, each ml of water requires one calorie to go up 1 degree Celsius, so this liter of water takes 1000 calories to go up 1 degree Celsius. (There are 1000 ml, each of which needs to have its temperature raised.)
Answer:
33 g.
Explanation:
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In this case, for these particle-mole-mass relationships problems, it is necessary for us to recall the following equivalence statement, based off the molar mass of the involved compound, C3H8, one mole of particles and the Avogadro's number:

In such a way, we can set up the following expression for the calculation of the mass in the given particles of propane:

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Answer:
2HNO3 +Na2CO3 → CO2 + H2O + 2NaNO3
I'm not understanding that much. but if i'm right the answer is <span>3.84 x 10^-19 J</span>
Answer:
A , B, C
Explanation: D is a Diamagnetic