All categories

2 years ago

Rounded to the nearest whole number, how many neutrons, on average, are in an atom of osmium?

Physics

2 answers:

sergejj [24]2 years ago

7 0

Answer: 114

Explanation:

Osmium: It is hard, brittle transition metal.

Chemical symbol: Os

Atomic number, Z = 76

Number of protons = Atomic number = 76

Mass Number, A = 190.23 ≈ 190

Mass number = number of protons + number of neutrons

⇒190 = 76 + n

⇒n = 190 - 76

⇒n = 114

Thus, the atomic number of an atom of Osmium is 114.

andrey2020 [161]2 years ago

4 0

Answer: 114

Explanation:

The mass number of an element gives the sum of the protons and the neutrons inside the nucleus of one atom of that element, while the atomic number of an element gives the number of protons inside one atom of that element.

We can infer the number of neutrons inside one atom of Osmium from its mass number and atomic number.

The atomic number of osmium is 76, so each atom of osmium has 76 protons

The (average) mass number of osmium is 190, so each atom of osmium has (on average) 190 protons+neutrons

So, in order to find the average number of neutrons, we can subtract the atomic number from the mass number:

$N=A-Z=190-76=114$

You might be interested in

An amusement park ride raises people high into the air, suspends them for a moment, and then drops them at a rate of free-fall a

blsea [12.9K]

Answer: apparent weighlessness.

Explanation:

1) Balance of forces on a person falling:

i) To answer this question we will deal with the assumption of non-drag force (abscence of air).

ii) When a person is dropped, and there is not air resistance, the only force acting on the person's body is the Earth's gravitational attraction (downward), which is the responsible for the gravitational acceleration (around 9.8 m/s²).

iii) Under that sceneraio, there is not normal force acting on the person (the normal force is the force that the floor or a chair exerts on a body to balance the gravitational force when the body is on it).

2) This is, the person does not feel a pressure upward, which is he/she does not feel the weight: freefalling is a situation of apparent weigthlessness.

3) True weightlessness is when the object is in a place where there exists not grativational acceleration: for example a point between two planes where the grativational forces are equal in magnitude but opposing in direction and so they cancel each other.

Therefore, you conclude that, assuming no air resistance, a person in this ride experiencing apparent weightlessness.

3 0

2 years ago

Read 2 more answers

What two simple machines are found in a bike?

omeli [17]

I think it's a pulley and a lever.

3 0

3 years ago

You need to determine the density of a ceramic statue. if you suspend it from a spring scale, the scale reads 32.4 n . if you th

Mandarinka [93]

Well, the density of the water is
${1000 \frac{kg}{ {m}^{3} } }$
so i believe that is what the question is asking for :)

4 0

3 years ago

A ball is dropped from a cliff. determine how far the ball fell after 7.5 seconds

grin007 [14]

Answer:

The ball fell 275.625 meters after 7.5 seconds

Explanation:

If an object is left on free air (no friction), it describes an accelerated motion in the vertical direction, powered exclusively by the acceleration of gravity. The formulas needed to compute the different magnitudes involved are

$V_f=gt$

$\displaystyle y=\frac{gt^2}{2}$

Where $V_f$ is the final speed of the object in free fall, assumed positive downwards, t is the time elapsed since the release and y is the vertical distance traveled by the object

The ball was dropped from a cliff. We need to calculate the vertical distance the ball went down in t=7.5 seconds. We'll use the formula

$\displaystyle y=\frac{gt^2}{2}$

$\displaystyle y=\frac{(9.8)(7.5)^2}{2}$

$Y=275.625\ m$

5 0

3 years ago

You took a running leap off a high diving platform. You were running at 3.1 m/s and hit the water 2.4 seconds later. How high wa

rusak2 [61]

The distance you free-fall from rest is D = (1/2) (g) (T²) <== memorize this

Height of the platform = (1/2) (9.8 m/s²) (2.4 sec)²

Height = (4.9 m/s²) (5.76 s²)

Height = (4.9/5.76) meters

Height = 28.2 meters (a VERY high platform ... about 93 ft off the water !)

Without air-resistance, your horizontal speed doesn't change. It's constant. Traveling 3.1 m/s for 2.4 sec, you cover (3.1 m/s x 2/4 s) = 7.4 m horizontally.

7 0

3 years ago