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ExtremeBDS [4]
3 years ago
5

Rounded to the nearest whole number, how many neutrons, on average, are in an atom of osmium?

Physics
2 answers:
sergejj [24]3 years ago
7 0

Answer: 114

Explanation:

Osmium: It is hard, brittle transition metal.

Chemical symbol: Os

Atomic number, Z = 76

Number of protons = Atomic number = 76

Mass Number, A = 190.23 ≈ 190

Mass number = number of protons + number of neutrons

⇒190 = 76 + n

⇒n = 190 - 76

⇒n = 114

Thus, the atomic number of an atom of Osmium is 114.

andrey2020 [161]3 years ago
4 0

Answer: 114

Explanation:

The mass number of an element gives the sum of the protons and the neutrons inside the nucleus of one atom of that element, while the atomic number of an element gives the number of protons inside one atom of that element.

We can infer the number of neutrons inside one atom of Osmium from its mass number and atomic number.

The atomic number of osmium is 76, so each atom of osmium has 76 protons

The (average) mass number of osmium is 190, so each atom of osmium has (on average) 190 protons+neutrons

So, in order to find the average number of neutrons, we can subtract the atomic number from the mass number:

N=A-Z=190-76=114

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The density of water at 22.3 degrees Celsius is 72.14 degrees .
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3 years ago
In tae-kwon-do, a hand is slammed down onto a target at a speed of 14 m/s and comes to a stop during the 3.0 ms collision. Assum
GrogVix [38]

Answer:

A) The impulse is 11,7 kg.m/s .  B) The average force on the hand is 3900N

Explanation:

Givens:

Hand's mass (m)= 0,90kg

Hand's initial velocity (vi)= 14m/s

Time of collision (t)= 3ms

<u>A) Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time. We use the formula:</u>

<em />

<em>/F/ = m. /Δv/</em>

<u>Where:</u>

F= Force of Impulse

m= Mass

Δv= change in speed ( vf-vi)

Using that formula we get:

/F/= 0,90kg . / (0m/s-14m/s) /

/F/=0,90kg . 14m/s

<em>/F/ = 11,7 kg. m/s</em>

*note that (vf) is 0 because the hand stops in the action, so it's final

velocity = 0

<u>B)The average force is equal to the change in the momentum over the change in time. We use the formula:</u>

<em>/F/= m. (Δv) : Δt</em>

<u>Where:</u>

F= the average force from the target

m= the mass of the hand

Δv= hange in speed (vf/vi)

Δt= change in time

*if we look closely, we find the we alredy have half of the equation because we have alredy calculated m.(Δv) in point A.

We boil the equation down to:

/F/= Impulse : Δt

/F/= 11,7kg.m/s : 0,003s

<em>/F/= 3900N</em>

*we use 0,003s as our time because the given time was 3ms.

*the final result is expressed in Newtons because our final result ends up beeing <em>kg.m/s²</em> = N

<u />

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4 years ago
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Answer:

F = - 1,598 10⁻³ N

Explanation:

Electic strength is given by Coulomb's law

          F = k q₁ q₂  / r²

Where k is the Coulomb constant that is worth 8.99 10⁸ N m²/C², q₁ and q₂ are the charges and r is the distance that separates the electric charges

In this case the charge of the two spheres is the same and of a different sign since when you remove the charge of a sphere that was initially neutral, it is left with that charge removed but of the opposite sign

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Let's calculate

       F = - 8.99 10⁸ (4.0 10⁻⁶)² / 0.30²

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5 0
3 years ago
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