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gizmo_the_mogwai [7]
3 years ago
8

Determine the heat given off to the surroundings when 9.0 g of aluminum (fm = 26.98) reacts according to the equation 2al + fe2o

3 → al2o3 + 2fe, δh°rxn= –849 kj/mol
Chemistry
1 answer:
Akimi4 [234]3 years ago
8 0

Hey there!:

Number of moles:

Molar Mass Al = 26.98 g/mol

n = mass / molar mass

n = 9.0 / 26.98

n = 0.3336 moles of Al

Given the reaction :

2 Al + Fe2O3 = Al2O3 + 2 Fe

From the equation, 2 moles of Al give off 849 kJ of heat :

Actual heat given off :

0.3336 / 2 * 849 =

0.3336 / 1698 = 1.4*10² Kj


Hope that helps!


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How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?
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Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

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