Answer:
q₃=5.3nC
Explanation:
First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:
Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:
In words, the value of q₃ must be 5.3nC.
Answer:
450000 kg m/s
Explanation:
convert 108km/h to m/s
1km=100m
1h=(60×60)s = 3600s
108km/h= (108×1000)÷3600
=30m/s
K.E =1/2mv^2
=1/2(1×10^3)(30^2)
= 1/2 × 1000 × 900
= 450000 kg m/s
this should be your answer, hope I was able to help.
For a chlorine atom to become a chloride ion, it must gain an electron.The chloride ion has a negative charge and is written as Cl-. Chlorine gains an electron because it has seven valence electrons, and to be a full octet, it gains an electron.
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Answer:
ω = 3.1 rad/s
θ = 36° from vertical
Explanation:
I will ASSUME that the bob and string is acting as a pendulum.
Please understand that the string will break when the bob is at the lowest point of the swing where the vectors of gravity and centripetal acceleration align. It will NOT break at the angle of maximum inclination measured from vertical. This angle is only a component of the maximum potential energy that gets converted to maximum kinetic energy at the lowest point of the swing.
At the bottom of the swing, the string must support the weight of the bob plus supply the required centripetal acceleration.
F = mg + mω²R
F/m = g + ω²R
F/m - g = ω²R
ω = √((F/m - g)/R)
ω = √((3/0.220 - 9.8)/0.40)
ω = 3.09691...
ω = 3.1 rad/s
Potential energy will convert to kinetic energy
mgh = ½mv²
h = v²/2g
R - Rcosθ = v²/2g
R(1 - cosθ) = v²/2g
1 - cosθ = v²/2gR
cosθ = 1 - v²/2gR
cosθ = 1 - (Rω)²/2gR
cosθ = 1 - Rω²/2g
cosθ = 1 - 0.40(3.1²)/(2(9.8))
cosθ = 0.804267
θ = 36.46045...
θ = 36°
Answer:
The Anti Reflective Coating on a solar cells helps to increase the amount of light absorbed into the cell. This anti reflective coating is very much needed as the reflection of a bare silicon solar cells is over 30%. For the thin AR Coating, silicon nitride or titanium oxide is used.
Explanation:
hope this help:)
