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Alecsey [184]
3 years ago
14

Compute the following and give your answer in scientific notation

Chemistry
1 answer:
lana66690 [7]3 years ago
4 0

Answer:

5.7 × 10⁻³

Explanation:

3.51 - 2.94 = 0.57

Don't change the scientific notation.

0.57 × 10⁻²

BUT

The "0" is not applicable so move the decimal point to the right by one and subtract the power by one.

5.7 × 10⁻²⁻¹ = 5.7 × 10⁻³

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A solution of H2SO4 (90.08 g/mol) has 785.6 g of H2SO4 and 359 g of H2O. What is the molal concentration (molality)?
tekilochka [14]

The molality of H₂SO₄ solution is 24.2 m.

<u>Explanation:</u>

We need to find the molality of sulfuric acid.

Mass of sulfuric acid = 785.6 g

Mass of water = 359 g

We have to find the moles of H₂SO₄ by using its mass and molar mass as,

Moles of H₂SO₄ = $\frac{785.6g}{90.08 g/mol}

                         = 8.7 moles

Mass of the solution in kg =$\frac{359}{1000} =  0.359 kg

Molality = $\frac{moles}{solvent (kg)}

           = $\frac{8.7 mol }{0.359 kg}\\

          = 24.2 m

So molality of the H₂SO₄ solution is 24.2 m.

8 0
3 years ago
Fill out the table to identify the number and name of each group and some basic properties shared by the elements in that group.
ivolga24 [154]

Answer:

1st column group 1 - group2

second column Halogen group - zero group ( inert gases )

third column - very active metals , tend to lose one electron -less reactive than group one , tend to  lose 2 electrons - very active nonmetals, tend to gain one electron - Nobel gases , do not gain or lose electrons

Explanation:

7 0
3 years ago
Read 2 more answers
a chemist want to make a solution of 3.4M HCl there are tow solutions of HCl that he can find on the shelf. one has a concentrat
steposvetlana [31]

Answer:

The most concentrated one, 6.0 M.

Explanation:

A simple and reliable way to produce a solution of HCl (or anything else, for that matter) is to use a more concentrated solution and dilute it.

In this case the chemist could take a portion of the 6.0 M solution and dilute it by adding water, until the concentration is 3.4 M.

Such a process would not be possible with the 2.0 N (which is the same as 2.0 M for HCl) solution.

7 0
3 years ago
Determine the amount of heat energy in joules required to raise the temperature of 7.40g of water from 29.0OC to 46.0 OC.
valina [46]

Answer: The amount of heat energy in joules required to raise the temperature is 526 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m= mass of substance = 7.40 g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 29.0°C

Final temperature of the water = T_f  = 46.0°C

Change in temperature ,\Delta T=T_f-T_i=(46.0-29.0)^0C=17.0^0C

Putting in the values, we get:

Q=7.40g\times 4.184J/g^0C\times 17.0^0C

Q=526J

The amount of heat energy in joules required to raise the temperature is 526 Joules

4 0
3 years ago
Real gas expansion in a vacuum is exothermic or endothermic?
lisov135 [29]
I think it is exothermic
3 0
4 years ago
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