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Sidana [21]
3 years ago
11

PLEASEEEE HELPPPPP ASAP!!!!!

Chemistry
2 answers:
Wewaii [24]3 years ago
8 0

Answer: Adding a reactant will shift the reaction towards the products.

Adding a product will shift the reaction towards the reactants.

Removing a reactant will shift the reaction towards the reactants.

Removing a product will shift the reaction towards the products.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Adding a reactant will increase the concentration of reactants and hence the reaction will try to undo the increase by shifting  the reaction towards the products.

Adding a product will increase the concentration of products and hence the reaction will try to undo the increase by shifting the reaction towards the reactants.

Removing a reactant will decrease the concentration of reactants and hence the reaction will try to undo the decrease by shifting  the reaction towards the reactants.

Removing a product will decrease the concentration of products and hence the reaction will try to undo the decrease by shifting  the reaction towards the products.

Alex3 years ago
5 0

Answer:

Adding a reactant  - shift towards product

Adding a product  - shift towards reactant

Removing a reactant  - shift towards reactant

Removing a product- shift towards product

Explanation:

a) Reactant added – When a reactant is added to a chemical reaction which has not yet reached the equilibrium, then the added reactant is partially consumed and the reaction shifts towards the product. However, there is no effect on the K value

b) Adding a product – When a product is added, then it is partially consumed and the reaction shifts towards the reactant. Again, there is no change in K value.  

c) Removing a reactant – The reaction will shift towards the reactant

d) Removing a product- The reaction will shift towards the product

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3 years ago
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Which atom in the ground state has a partially filled second electron shell?
serious [3.7K]
Atoms have electrons filled in energy shells.
1. H - hydrogen atom has one electron in the First energy shell. Therefore hydrogen has a partially filled first energy shell

2.Li - Li electron configuration is 2,1
The outermost energy shell is the second energy shell in which there is only one electron
Therefore the second energy shell is partially filled. This is the correct answer

3. K - electron configuration is 2,8,8,1
The outermost energy shell is the fourth energy shell which is partially filled. The second energy shell is completely filled

4.Na - electron configuration is 2,8,1
The outermost energy shell is the third energy shell which is partially filled
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4 0
3 years ago
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Which number represents an acidic pH, 4 or 9? _______ Numerical Answers Expected! Answer for Blank 1:
Tasya [4]

Answer:

4

Explanation:

pH scale of acidic is 4.

8 0
3 years ago
Hydrogen and iodine react to form hydrogen iodide, like this: H_2 (g) + I_2 (g) rightarrow 2 HI(g) Also, a chemist finds that at
telo118 [61]

This is an incomplete question, here is a complete question.

Hydrogen and iodine react to form hydrogen iodide, like this:

H_2(g)+I_2(g)\rightarrow 2HI(g)

Also, a chemist finds that at a certain temperature the equilibrium mixture of hydrogen, iodine, and hydrogen iodide has the following composition:

Compound            Pressure at equilibrium

H_2                                   61.8 atm

I_2                                    46.5 atm

HI                                  52.3 atm

Calculate the value of the equilibrium constant K_p for this reaction. Round your answer to 2 significant digits.

Answer : The value of equilibrium constant K_p for this reaction is, 0.952

Explanation :

The given chemical reaction :

H_2(g)+I_2(g)\rightarrow 2HI(g)

The expression of K_p for above reaction follows:

K_p=\frac{(P_{HI})^2}{P_{H_2}\times P_{I_2}}

We are given:

P_{H_2}=61.8atm

P_{I_2}=46.5atm

P_{HI}=52.3atm

Putting values in above equation, we get:

K_p=\frac{(52.3)^2}{61.8\times 46.5}\\\\K_p=0.952

Therefore, the value of equilibrium constant K_p for this reaction is, 0.952

7 0
3 years ago
Which temperature in Celsius (°C) does this thermometer show? –8° 0° 25° 32°
natka813 [3]

Answer:

0° Celsius

Explanation:

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