All categories

2 years ago

A plane travels 5.0 X 10^2 m while being accelerated uniformly from rest at the rate of

Physics

1 answer:

Crank2 years ago

7 0

Answer:

The final velocity of the plane is 100 m/s.

Explanation:

To solve this problem, we will use one the kinematics equations. First, let's write out what information we have given and what we are trying to find.

x = 5.0 * 10^2 m

a = 5.0 m/s^2

v1 = 0 m/s (starts from rest)

v2 = ? (we are trying to find the final velocity)

Using the variables listed above, we can select the following equation to use:

v2^2 = v1^2 + 2ax

Now, we should plug in our known values and isolate the unknown variable.

v2^2 = 0 + 2(10)(500)

To solve for the velocity, we should take the square root of both sides of the equation to get rid of the square on the left side of the equation.

v = sqrt(10,000)

Now, we must simplify the right side of the equation to solve for v (the unknown variable).

v = 100 m/s

Therefore, your answer is 100 m/s.

Hope this helps!

You might be interested in

Explain with one example that different types of organisums live in one habitation

inn [45]

Answer:

When you look at a simple koi pond you can find Koi (the secondary consumer) that feeds off of the zooplankton (first consumer), they eat the phytoplankton (producers). All in a simple food chain

Explanation:

Basically, Koi eat the little animal plankton (zooplankton) that then eats the plant plankton (phytoplankton) that can only end when a part of that habitat is removed. If you got rid of the plant plankton then the whole chain would collapse and most likely die.

5 0

2 years ago

Which contemporary subfield focuses on assessing and treating people with mental disorders?

Vlada [557]

Psychiatry assesses and treats people with mental disorders

3 0

3 years ago

Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 3.18 m away from a waterfall 0.294 m in heigh

Karolina [17]

Answer:

v = 7.65 m/s

t = 0.5882 s

Explanation:

We are told that the salmon started downstream, 3.18 m away from a waterfall.

Thus, range = 3.18 m

Since the horizontal velocity component is constant, then;

Range = vcosθ × t

Thus,

vcosθ × t = 3.18 - - - (eq 1)

We are told the salmon reached a height of 0.294 m

Thus, using distance equation;

s = v_y•t + ½gt²

g will be negative since motion is against gravity.

s = v_y•t - ½gt²

Thus;

0.294 = v_y•t - ½gt²

v_y = vsinθ

Thus;

0.294 = vtsinθ - ½gt² - - - (eq 2)

From eq(1), making v the subject, we have;

v = 3.18/tcosθ

Plugging into eq 2,we have;

0.294 = (3.18/tcosθ)tsinθ - ½gt²

0.295 = 3.18tanθ - ½gt²

We are given g = 9.81 m/s² and θ = 45°

0.295 = (3.18 × tan 45) - ½(9.81) × t²

0.295 = 3.18 - 4.905t²

3.18 - 0.295 = 4.905t²

4.905t² = 2.885

t = √2.885/4.905

t = 0.5882 s

Thus;

v = 3.18/(0.5882 × cos45)

v = 7.65 m/s

8 0

2 years ago

If the charges attracting each other in the preceding problem have equal magnitudes,show that the magnitude of each charge is 2.

Schach [20]

Answer:

The magnitude of each charge is $2.82\times10^{-6}\ C$

Explanation:

Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.

We need to calculate the magnitude of each charge

Using formula of force

$F=\dfrac{kq^2}{r^2}$

Where, q = charge

r = separation

Put the value into the formula

$20=\dfrac{9\times10^{9}\times q^2}{(6\times10^{-2})^2}$

$q^2=\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}$

$q=\sqrt{\dfrac{(6\times 10^{-2})^2\times20}{9\times10^{9}}}$

$q=2.82\times10^{-6}\ C$

Hence, The magnitude of each charge is $2.82\times10^{-6}\ C$

6 0

3 years ago

Which value is equivalent to 178 centimeters?

tester [92]

178 centimeters is exactly, precisely, the same length as ...

-- 0.00178 kilometer
-- 1.78 meters
-- 1,780 millimeters
-- 1,780,000 micrometers
-- 1,780,000,000 nanometers

7 0

3 years ago