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harina [27]
2 years ago
15

A plane travels 5.0 X 10^2 m while being accelerated uniformly from rest at the rate of

Physics
1 answer:
Crank2 years ago
7 0

Answer:

The final velocity of the plane is 100 m/s.

Explanation:

To solve this problem, we will use one the kinematics equations.  First, let's write out what information we have given and what we are trying to find.

x = 5.0 * 10^2 m

a = 5.0 m/s^2

v1 = 0 m/s (starts from rest)

v2 = ? (we are trying to find the final velocity)

Using the variables listed above, we can select the following equation to use:

v2^2 = v1^2 + 2ax

Now, we should plug in our known values and isolate the unknown variable.

v2^2 = 0 + 2(10)(500)

To solve for the velocity, we should take the square root of both sides of the equation to get rid of the square on the left side of the equation.

v = sqrt(10,000)

Now, we must simplify the right side of the equation to solve for v (the unknown variable).

v = 100 m/s

Therefore, your answer is 100 m/s.

Hope this helps!

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A spherical capacitor is formed from two concentric sphericalconducting shells separated by vacuum. The inner sphere has radius1
zubka84 [21]

Explanation:

(1).  Formula to calculate the potential difference is as follows.

       \Delta V = -\int E dr

                  = -\int \frac{kq}{r^{2}} dr

                 = \frac{kq}{r_{f}} - \frac{kq}{r_{i}}

                 = \frac{kq(r_{f} - r_{i})}{r_{f}r_{i}}

                 = \frac{9 \times 10^{9} \times 3.30 \times 10^{-9}(0.1 - 0.015)}{0.1 \times 0.015}

                = 38.7 volts

Therefore, magnitude of the potential difference between the two spheres is 38.7 volts.

(2).  Now, formula to calculate the energy stored in the capacitor is as follows.

           E = \frac{1}{2}QV

              = \frac{1}{2} \times 3.30 \times 10^{-9} \times 3.87 V

              = 6.39 \times 10^{-8} J

Thus, the electric-field energy stored in the capacitor is 6.39 \times 10^{-8} J.

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2 years ago
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3 years ago
Convert 1.5 radian into milliradians.
Alex

Answer:

1500 milliradians

Explanation:

Data provided in the question:

1.5 radians

Now,

1 radians consists of  1000 milliradians

1 milli = 1000

thus for the 1.5 radians, we have

1.5 radians = 1.5 multiplied by 1000 milliradians

or

1.5 radians = 1500 milliradians

Hence, after the conversion

1.5 radians equals to the value 1500 milliradians

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6 An infinite non-conducting sheet has a surface charge density o = 5.80pC/m². (a) How
Anit [1.1K]

a. Work done = 2. 0648 Joules

b. Electrical potential, V = 4. 03 × 10^10 volts

<h3>How to determine the parameters</h3>

a. Work done = force × distance

Force = density × acceleration due to gravity

Force = 5. 80 × 10

Force = 58 Newton

We have that distance = 3. 56cm = 0. 0356 m

Work done = 58 × 0. 0356

Work done = 2. 0648 Joules

b. The formula for electric potential is given thus,

Electric potential, V = k\frac{q}{r}

r = 0. 0356m

k = Coulomb's constant = 8.98*10^9kg⋅m3⋅s−4⋅A−2.

q= 1.60x10^-¹C

substitute into the formula

Electric potential, V = 8. 98 × 10^9 × \frac{1. 6 * 10^-^-1}{0. 0356}

Electric potential, V = 8. 98 * 10^9 × 4. 494

Electric potential, V = 4. 03 * 10^1^0 volts

Learn more about electric potential here:

brainly.com/question/14812976

#SPJ1

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