Air can go in any direction. . .
Answer:
1. b. The door is exerting a centripetal force on you that balances the centrifugal force of the turn.
2. b. There is no net force acting on the object.
Explanation:
1. This is because as you move to the right due to the centrifugal force of the turn, a corresponding centripetal force acts on you due to the door which does not allow you fall out of the car since,<u> the door is exerting a centripetal force on you that balances the centrifugal force of the turn. </u>
So, the answer is b
2. This is because, since the object moves at a constant speed and thus does not accelerate, no net force can act on it since, a net force would imply that the object accelerates. Note that a constant speed does not imply that no force acts on it. It only shows that the resultant or net force is zero since the object does not accelerate.
So, <u>there is no net force acting on the object. </u>
So, b is the answer.
Answer: 8.8e-3 rad/s², 0.0 m/s²
Explanation:
R = 35 / 2 = 17.5 m
a = 2.3 m/s / 15 s = 0.1533333... m/s²
α = a/R = 0.1533333/17.5 = 0.0087619... ≈ 8.8e-3 rad/s² ◄(a)
at maximum speed, no more acceleration in either tangential or angular
α = a = 0.0 rad/s² or m/s² ◄(b)
If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positive number in meters, will the bullet hit if aimed directly at a target 180 m away
The muzzle velocity of the bullet is 275 m/s
Answer:
y = -1.1109 m
Explanation:
Range = 
range = 85 m
velocity = 275 m/s
g = 9.8 m/s²
If the bullet is aimed at a target 180 m, time required to travel 180 m with horizontal component will be;
t = 0.6546 sec
To determine, how low as a positive number in meters.
y = 
y = 0.9909 - 2.1018
y = -1.1109 m
