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podryga [215]
3 years ago
15

PLEASE HELP

Physics
1 answer:
enyata [817]3 years ago
8 0

Answer:

29 m/s.

Explanation:

Hope this helps.

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What molecular geometry would be expected for f2 and hf?
Kaylis [27]
The molecular geometry of both F2 and HF is linear.

There are only two atoms which are covalently bonded and thus, the bonding scheme with the atoms looks like this;

F --- F

H---F

So, both are linear.

4 0
3 years ago
You need to focus a 10 mW, 632.8 nm Gaussian laser beam that is 5.0 mm in diameter into a sample. You have access to a lens with
Anna [14]

Answer:

ee that the lens with the shortest focal length has a smaller object

           

Explanation:

For this exercise we use the constructor equation or Gaussian equation

        \frac{1}{f}  = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distance to the object and the image respectively.

Magnification a lens system is

          m = \frac{h'}{h} = - \frac{q}{p}

             h ’= -\frac{h q}{p}

In the exercise give the value of the height of the object h = 0.50cm and the position of the object p =∞

Let's calculate the distance to the image for each lens

f = 6.0 cm

           \frac{1}{q} = \frac{1}{f }  - \frac{1}{p}

as they indicate that the light fills the entire lens, this indicates that the object is at infinity, remember that the light of the laser rays is almost parallel, therefore p = inf

          q = f = 6.0 cm

for the lens of f = 12.0 cm q = 12.0 cn

to find the size of the image we use

           h ’= h q / p

where p has a high value and is the same for all systems

           h ’= h / p q

Thus

f = 6 cm h ’= fo 6 cm

 

f = 12 cm h ’= fo 12  cm

therefore we see that the lens with the shortest focal length has a smaller object

8 0
3 years ago
The uniform 100-kg I-beam is supported initially by its end rollers on the horizontal surface at A and B. by means of the cable
Ann [662]

I attached a free body diagram for a better understanding of this problem.

We start making summation of Moments in A,

\sum M_A = 0

P(6cos\theta)-981(4cos\theta)=0

P=654N

Then we make a summation of Forces in Y,

\sum F_y = 0

654+R-981 = 0

R=327N

At the end we calculate the angle with the sin.

sin\theta = \frac{3m}{4m+2m+2m} = \frac{3m}{8m}

\theta = 22.02\°

8 0
3 years ago
Technician A says that the accumulator is on the high-pressure side of the refrigerant system. Technician B says that the receiv
pychu [463]

Question:

The options are

a. Technician A only

b. Technician B only

c. Both A and B

d. Neither A nor B

Answer:

The correct option is

d. Neither A nor B

Explanation:

Here, we note that to locate the receiver/driers we look at the high-pressure side of refrigerant system normally around the tubes in between the expansion valve outlet and the condenser outlet and connected to the condenser.

While the accumulator can be found, attached to the evaporator outlet within the low pressure side of the refrigerant system.

Therefore, neither Technician A nor B is correct.

6 0
3 years ago
Fish are able to acquire the oxygen needed for respiration under water using gills. This is an example of which type of adaptati
stiks02 [169]

Answer:

Structural

Explanation:

Structural adaptations are a change to a organism's body, gills are part of the fish's body which would be why this is a structural adaptation!

Hope this helped! Stay safe have a good day or night!

3 0
3 years ago
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