Select the correct exercise category for each of the specific ways to increase intensity

Will the star of bethlehem be visible on december 21st

nikklg [1K]

Answer:

The best time to view the spectacle on Dec. 21 will be around an hour after sunset.

8 0

3 years ago

A ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the b

Mariulka [41]

We have centripetal acceleration = $v^2/r = 2g$

So, v = $\sqrt{2gr}$

Now by equation of motion we have S= ut +0.5a $t^2$

S =displacement, u = initial velocity, a= acceleration and t = time

Here S = 2r and a = g , u = 0

$2r = 0+\frac{1}{2} *g*t^2$

$t = \sqrt{\frac{4r}{g} }$

Distance traveled in horizontal direction = $\sqrt{2gr}*\sqrt{\frac{4r}{g} }= \sqrt{8r^2} =2r\sqrt{2}$

8 0

4 years ago

A hot-air balloon is rising straight up with a speed of 4.6 m/s. a ballast bag is released from rest relative to the balloon at

kherson [118]

The time taken by the ballast bag to reach the ground is 2.18 s

The ballast bag at rest with respect to the balloon has the upward velocity (u) of 4.6 m/s , which is the velocity of the balloon. When it is dropped from the balloon, its motion is similar to an object thrown upwards with an initial velocity u and it falls under the acceleration due to gravity g.

Taking the upward direction as positive and the downward direction as negative, the following equation of motion may be used.

$s=ut+\frac{1}{2}at^2$

The bag makes a net displacement s of 13.4 m downwards, hence

$s=-13.4 m$

Its initial velocity is

$u=+4.6 m/s$

The acceleration due to gravity acts downwards and hence it is negative.

$g=-9.8 m/s^2$

Use the values in the equation of motion and write an equation for t.

$s=ut+\frac{1}{2} at^2 \\ -13.4=4.6t-\frac{1}{2}(9.8)t^2\\ 4.9t^2-4.6t-13.4=0$

Solving the equation for t and taking only the positive value for t,

t=2.18 s

4 0

3 years ago

A person uses a surfboard to ride every 30th wave crest towards the beach. The wave crest travels at a speed of 1.6m/s and the d

pashok25 [27]

Answer:

8

Explanation:

Applying,

v = λf................ Equation 1

Where v = velocity/ speed of the wave, λ = wave length of the wave, f = number of waves the person surf in one seconds.

make f the subject of the equation

f = v/λ............ Equation 2

From the question,

Given: v = 1.6 m/s, λ = 24 m

Substitute these values into equation 2

f = 1.6/24

f = 0.0667 wave/seconds.

If,

in one seconds, the person surf a total wave crest of 0.0667

Therefore,

in one hours, he will surf a total wave crest of (0.0667×60×60) = 240 waves crest

He rides for every 30th wave crest,

Hence,

number of wave crest the person surf in one hour = 240/30 = 8

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Ivanshal [37]

If the wavelength increases (gets longer), then the frequency decreases.

(A wave occurs less often.)

7 0

3 years ago