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kherson [118]
3 years ago
11

Select the correct exercise category for each of the specific ways to increase intensity

Physics
1 answer:
Alecsey [184]3 years ago
3 0
The answer is cardiovascular.
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Which transition represents a time when water molecules are moving closer together?
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The best transition between the four options presented to represent a time when water molecules are moving closer together would be A. Frost forms on a window pane.

The closest distance that the water molecules can do is when the water is in the state of being solid. It is known that the solid state of matter has the closest distance from molecule to molecule that when a molecule tries to move, the others move as well creating a vibration and thus producing heat in the process. When they are in a liquid state, they are quite far from each other. In a gas state, they really are far from each. This explains the difference in their characteristics.
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What elements make gas
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Why does refraction occur?
irina1246 [14]

Answer:

The answer is C.

Explanation:

Let's take a glass of water as an example. Now, shine a flashlight on it. See it bend the light into a rainbow? That is a example of refraction. When the light enters the water, the water actually slows down and changes its direction, causing the light to come out the other side in a different way. Since water is very dense, it can bend the water and make it different.

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3 years ago
Pay it forward! Answer a questio1) For a positive point charge, the lines radiate ………. . While, for a negative point charge, the
nikitadnepr [17]

Explanation:

1) For a positive point charge, the lines radiate outwards

for a negative point charge, the lines converge inwards

2) F = 2.3 X 10^-26 N

k = 9 X 10^9 N.m²/C

q1 = q2 = e = 1.6 X 10^-19 C

r = ?

F = kq1q2/r²

r² = kq1q2/F

r = √[kq1q2/F ]

r = √0.0100

r = 0.10m

The two protons are 0.10 m apart

3) The unit if electric field intensity is Newton-per-coulomb N/C

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3 years ago
Light of wavelength 550 nm falls on a slit that is 3.50 x 10^-3 mm wide. How far from the central . maximum will the first diffr
myrzilka [38]
Λ= 550 * 10^{-9}\] m.&#10;&#10;D = 3.50*10^-6 m.
d = 10 m. &#10;&#10;m = 1&#10;&#10;2x = ?

Then you need to find x when n=1
or 
sinθ=λ/w=524x10^-9/0.0033=1.59x10^-4
≈θ for θ<<1 , so θ=1.59x10^-4 radians

Then you can find rhe distance of<span> bright fringe from the center:</span>d= θD=1.59x10^-4x10m ≈ 1.6 mm
6 0
3 years ago
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