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I am Lyosha [343]
3 years ago
14

If the mass of 293nv is 293.15 amu and that of 295nv is 295.30 amu , what is the atomic weight of nv?

Physics
1 answer:
expeople1 [14]3 years ago
5 0
Honestly, I am quite confused with what Nv stands for because there is no element with that symbol. However, I still get the concept of finding the average molecular mass of an element. Let's just assume that nv stands for a specific type of element and it has two isotopes: nv-293 and nv-295. Isotopes have the same number of protons but differ in mass number (protons+neutrons). 

To find the average atomic weight, just multiply the individual weights with the respective composition of the isotope. Since there are only two isotopes, they constitute 50% each. So, the average atomic weight is 

(50%)(293.15 amu) + (50%)(<span>295.30 amu) = 294.225 amu

Hence, the atomic weight of nv is 294.225 atomic mass units.</span>
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Rank the deformations of the following rods in terms of the magnitude of the average normal strain: (a) The length of a 1-m-long
kipiarov [429]

To solve this problem we will consider the concepts related to the normal deformation on a surface, generated when the change in length is taken per unit of established length, that is, the division between the longitudinal fraction gained or lost, over the initial length. In general mode this normal deformation can be defined as

\epsilon = \frac{\delta}{l} = \frac{l_0-l}{l}

Here,

\delta= Change in final length (l_0) and the initial length l

PART A)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{1.02-1}{1}

\epsilon = 0.01961

PART B)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{2-1.05}{2}

\epsilon = 0.475

PART C)

\epsilon = \frac{\delta_1}{l}

\epsilon = \frac{l_0-l}{l_0}

\epsilon = \frac{3.07-3}{3}

\epsilon = 0.0233

Therefore the rank of this deformation would be  B>C>A

7 0
3 years ago
Suppose you now take the ball and using a bat, pop it straight up into the air with a hang-time of 5.00 s (the hang time is how
dolphi86 [110]

Answer:

<h3>30.66m</h3>

Explanation:

Using the equation of motion formula S = ut + \frac{1}{2}gt^2 where;

S is the height to which the ball rises

u is the initial velocity of the ball = 0m/s

a is the acceleration due to gravity = 9.81m/s²

t is the time taken by the ball in air = 5.0s

Note that the  time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s

Substituting the given parameters into the formula above to get S:

S = ut + \frac{1}{2}gt^2\\\\S = 0(2.5)+ \frac{1}{2}(9.81)(2.5)^2\\\\S = 0+\frac{1}{2}(9.81)\times 6.25 \\\\S = \frac{61.3125}{2}\\ \\S = 30.65625m\\\\S \approx 30.66m

This means that the ball rises 30.66m before it reaches its peak.

8 0
3 years ago
in terms of mechanical advantage and velocity ratio write an expression for the efficiency of a simple machine​
mixer [17]

Answer:

Efficiency = (MA/VR) ×100%

8 0
3 years ago
Hello!
Mnenie [13.5K]

Answer:

T_0=80695.17162...

Explanation:

Given equation:

\ln \left(\dfrac{T_0-100}{T_0}\right)=-0.00124

To solve the given equation:

\textsf{Apply log rules}: \quad e^{\ln (x)}=x

\implies \dfrac{T_0-100}{T_0}=e^{-0.00124}

Multiply both sides by T₀:

\implies T_0-100=T_0e^{-0.00124}

Add 100 to both sides:

\implies T_0=T_0e^{-0.00124}+100

Subtract T_0e^{-0.00124} from both sides:

\implies T_0-T_0e^{-0.00124}=100

Factor out the common term T₀:

\implies T_0(1-e^{-0.00124})=100

Divide both sides by (1-e^{-0.00124})

\implies T_0=\dfrac{100}{1-e^{-0.00124}}

Carry out the calculation:

\implies T_0=\dfrac{100}{1-0.99876...}

\implies T_0=\dfrac{100}{0.001239231...}

\implies T_0=80695.17162...

6 0
3 years ago
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notka56 [123]
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