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I am Lyosha [343]
3 years ago
14

If the mass of 293nv is 293.15 amu and that of 295nv is 295.30 amu , what is the atomic weight of nv?

Physics
1 answer:
expeople1 [14]3 years ago
5 0
Honestly, I am quite confused with what Nv stands for because there is no element with that symbol. However, I still get the concept of finding the average molecular mass of an element. Let's just assume that nv stands for a specific type of element and it has two isotopes: nv-293 and nv-295. Isotopes have the same number of protons but differ in mass number (protons+neutrons). 

To find the average atomic weight, just multiply the individual weights with the respective composition of the isotope. Since there are only two isotopes, they constitute 50% each. So, the average atomic weight is 

(50%)(293.15 amu) + (50%)(<span>295.30 amu) = 294.225 amu

Hence, the atomic weight of nv is 294.225 atomic mass units.</span>
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Answer:

The velocity of the release is 4.9 m/s.

Explanation:

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s=ut+\frac{1}{2} at^{2}

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0=u-4.9

u=4.9 m/s

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3 years ago
Newton's cradle consists of an aligned row of identical elastic balls suspended by strings so they barely touch one another. whe
Ilia_Sergeevich [38]

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8 0
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You’re driving your car towards an intersection. A Porsche is stopped at the red light. You’re traveling at 36 km/h (10 m/s). As
34kurt

Your position at time t, relative to the stop line:

x_1=-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t

The Porsche's position:

x_2=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2

a. You pass the Porsche immediately after the time it takes for x_1=x_2:

-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=2.3\,\rm s

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c. At time t, the Porsche is moving at velocity

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6 0
3 years ago
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kirza4 [7]

Answer:

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average velocity = ( v1 + v2 + v3 + v4 ) / 4

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correct answer d)

The average velocity of the following 4 velocity measurements will be d) 8.7 m/s

To learn more about velocity here :

brainly.com/question/18084516

#SPJ1

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