To solve this problem we will consider the concepts related to the normal deformation on a surface, generated when the change in length is taken per unit of established length, that is, the division between the longitudinal fraction gained or lost, over the initial length. In general mode this normal deformation can be defined as

Here,
= Change in final length
and the initial length 
PART A)




PART B)




PART C)




Therefore the rank of this deformation would be B>C>A
Answer:
<h3>
30.66m</h3>
Explanation:
Using the equation of motion formula
where;
S is the height to which the ball rises
u is the initial velocity of the ball = 0m/s
a is the acceleration due to gravity = 9.81m/s²
t is the time taken by the ball in air = 5.0s
Note that the time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s
Substituting the given parameters into the formula above to get S:

This means that the ball rises 30.66m before it reaches its peak.
Answer:

Explanation:
Given equation:

To solve the given equation:


Multiply both sides by T₀:

Add 100 to both sides:

Subtract
from both sides:

Factor out the common term T₀:

Divide both sides by 

Carry out the calculation:


