he growth of baker's yeast (S. cerevisiae) on glucose may be simply described by following equation CH,,06 3 02 0.48 NH,-> 0.
48 C6H,,No, 4.32 H,O 3.12 CO2 yeast In a batch reactor of volume 10 1, the final desired yeast concentration is 50 gdw/1. a. Determine the concentration and total amount of glucose and (NH4),SO4 in the nutrient medium. b. Determine the yield coefficients YxIs (biomass/glucose) and Yro (biomass/oxygen). c. Determine the total amount of oxygen required. d. If the rate of growth at exponential phase is r, 0.7 gdw/l-h, determine the rate of oxygen consumption (g O,/1-h) e. Calculate the heat-removal requirements for the reactor (recall equation 6.26).
2 answers:
Complete Question (in order)
The growth of baker's yeast (S. cerevisiae) on glucose may be simply described by following equation:
C₆H₁₂0₆ + 30₂ + 0.48 NH₃ => 0.48C₆H₁₂NO₃ + 4.32H₂O + 3.12CO₂ yeast
In a batch reactor of volume 10 1, the final desired yeast concentration is 50 gdw/1.
a. Determine the concentration and total amount of glucose and (NH4)₂SO4 in the nutrient medium.
b. Determine the yield coefficients (biomass/glucose) and
(biomass/oxygen).
c. Determine the total amount of oxygen required.
d. If the rate of growth at exponential phase is = 0.7 gdw/l-h, determine the rate of oxygen consumption (g O₂/1-h)
e. Calculate the heat-removal requirements for the reactor (recall equation 6.26).
Answer:
a. 2.3 × 10⁴ kg
b. 0.384 and 0.72
c. 6.94 × 10³ kg
d. 0.973
Explanation:
The given equation that describes the growth of baker's yeast on glucose
C₆H₁₂0₆ + 30₂ + 0.48 NH₃ => 0.48C₆H₁₂NO₃ + 4.32H₂O + 3.12CO₂ yeast
The volume of batch reactor is given as 10⁵ Liters
The final desired yeast concentration is 50 gdw/l
The following attached documents gives additional solution for all other answers
You might be interested in
Complete Question
The complete question is shown on the first uploaded image
Answer:
X is Be
Y is B
Z is O
Explanation:
In order to understand the solution, we need to that the an element form a bond based on
1 The number of valence electron available in its atom
2 The number of electron it require to attains its stable state i.e its Octet state
The number of valence electron for each of the option are
F = 7, N = 5 , O = 6 , C = 4 , B = 3 , Be = 2
Considering the first element
We see that X is donating two valence electron in its atom and it is donating it to 2 Cl as Cl only requires a single electron to achieve its stable state
Now looking option we can see that Be has two valence electron in it atom and in order for it to attain its stable state it needs to release the electron so the correct option for this question is Be
Considering the second element
We see that Y is donating three valence electron in its atom and it is donating it to 3 Cl as Cl only requires a single electron to achieve its stable state
Now looking option we can see that B has three valence electron in it atom and in order for it to attain its stable state it needs to release the valence electron so the correct option for this question is B
Considering the second element
We see that Z is donating two valence electron in its atom and it is donating it to 2 Cl as Cl only requires a single electron to achieve its stable state, also Z has 2 lone-pair valence electron
Now looking at the option we can see that O has 6 valence electron so if it donates 2 valence electron it will still be left with 4 - pair of electron
Therefore the correct option to this question is O
