Now you try! Draw the arrows to represent the motion described, then calculate the distance
1 answer:
<h2>Answer:</h2>
Distance = 27m
Displacement = 3 metres South
<h2>Explanation:</h2>
Distance is a scalar quantity and it represents the length of the path taken by a body.
Displacement is a vector quantity and it represents the distance between the start and end points of a body.
Now to the question:
<em>The car drives 12 metres North i.e</em>
North (+ve)
∧
|
| 12m
|
|
<em>The car then drives 15 metres South i.e</em>
|
|
|
| 15m
|
∨
South (-ve)
(a) The car's distance d, is just the total distance covered to drive North and then South. i.e
d = 12m + 15m = 27m
(b) The car's displacement D, however takes into respect, the direction of the car as it drives to and fro.
Let North be taken as positive direction
Let South be taken as negative direction.
This means that;
12 m North = +12 m
15 m South = -15m
Therefore;
D = +12 - 15
D = -3m
Since the displacement is negative, then it means that the direction of the total displacement is South.
Therefore, the displacement is 3 metres South
PS: The arrow diagram has also been attached to this response
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Answer:
42.86m
Explanation:
The first thing we should keep in mind is that the watermelon moves with uniform acceleracion equal to gravity (9.81m / s ^ 2)
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
where
Vf=29m/s= final speed
Vo= initial speed=0m/S
g=gravity=9.81m/s^2
Y= distance traveled(m)
solving
the distance traveled by watermelon is 42.86m