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4 years ago

I NEED THIS DONE AS SOON AS POSSIBLE. PLEASE HELP ME

Physics

1 answer:

Ber [7]4 years ago

5 0

Circulation system. Blood to working muscles.

Skeleton supports movement and gives leverage

Breathing system. Need more O2 when muscles are working.

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Does the rock breathe ? No.

Does it grow ? No

Can it move by itself ? No

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3 DNA profile ?

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Word bank- (u may use more than once)

pishuonlain [190]

1 is idk
2 is solvent
3 is gamma rays
4 is transmutation
5 is nuclear fission
6 is nuclear fusion
7 is tracer
8 is half life
9 is
10 is strong force
11 is radioactivity
12 is dissociation
13 is unsaturated solution
14 idk
16 is alpha particle
17 is radioactivity
18 is concentration
19 is solubility
20 is saturated solution
21 is dissociation
22 is saturated solution
23 is saturated solution
24 is idk
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7 0

4 years ago

Why does conduction occur mainly in the lower atmosphere

Rus_ich [418]

Heat energy is transferred through Earth's atmosphere<span> in three ways: radiation,</span>conduction<span>, and convection. hoped this helped</span>

4 0

3 years ago

What is a core sample?

Andrew [12]

Answer:

it's a part of plate that moves with a plate that's the answer

4 0

3 years ago

A cylinder of gas at room temperature has a pressure . To p_{1} what temperature in degrees Celsius would the temperature have t

grandymaker [24]

In order to calculate the temperature, we need to know that temperature and pressure are directly proportional, that is, if the pressure increases, the temperature (in Kelvin) also increases in the same proportion.

So, first let's convert the temperature from Celsius to Kelvin, by adding 273 units:

$\begin{gathered} K=C+273 \\ K=20+273 \\ K=293 \end{gathered}$

Then, let's calculate the proportion:

$\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ \frac{p_1}{293}=\frac{1.5p_1}{T_2} \\ \frac{1}{293}=\frac{1.5}{T_2} \\ T_2=1.5\cdot293 \\ T_2=439.5\text{ K} \end{gathered}$

Now, converting back to Celsius, we have:

$\begin{gathered} C=K-273 \\ C=439.5-273 \\ C=166.5\text{ \degree{}C} \end{gathered}$

So the temperature would be 166.5 °C.

6 0

1 year ago

Consider the following 3 cases. (1) A block initially at rest on a floor is given a quick push by a hand. (2) The hand does not

jek_recluse [69]

Answer:

(1) The block isn't moving, despite the hand's force on it.

The net force on the block is zero.
The acceleration of the block is also zero.

(2) The block is gradually slowing down as it slides across the floor.

The acceleration of the block points in the opposite direction of the block's movement (i.e., the opposite direction of the block's velocity.)
The net force on the block points in the opposite direction of the block's movement. (Same direction as the block's acceleration.)

(3) Once again, the block is not moving.

The net force on the block is zero.
The acceleration of the block is also zero.

Explanation:

By Newton's Second Law, the net force on an object is in the same direction as its acceleration. Since this question said a lot about the object's motion, the direction of the object's acceleration might be easier to find than its net force.

The acceleration of an object is the rate of change of its velocity over time.

In this situation, the velocity of the object is zero, which is itself a constant. As a result, the rate of change of the object's velocity over time would be zero. Hence, the acceleration of the object would also be equal to zero. The zero vector doesn't have a specific direction.

By Newton's Second Law, the net force on the object is proportional to its acceleration. As a result, the net force on the object in this case would also be equal to zero. What about the hand's force on the block? The friction and normal force from the ground balances that force while the block hasn't yet started to move.

The object is slowing down over time. In other words, its velocity is decreasing over time. When a scalar value is decreasing, its rate of change would be negative. However, since velocity and acceleration are vectors, the acceleration of the object would be in the opposite direction of its velocity.

The net force on an object is in the same direction as its acceleration. As a result, the net force on this block in this case would also be in the opposite direction of the block's velocity.

Similar to the first situation, since the velocity of the block is zero (a constant,) its acceleration would be equal to zero. Since the net force on an object is proportional to its acceleration, the net force on this block would also be equal to zero.

7 0

3 years ago