Answer:
a). Vapour pressure = 2333.141 Pa
b). Percentage of atmospheric pressure = 99 %
c). Percentage of water vapour = 1.4 %
Explanation:
a). From water saturation pressure table,
Vapour pressure of water at 20°C is 17.5 torr
We know, 1 torr = 133.322 Pa
Therefore, 17.5 torr = 2333.141 Pa
Therefore, vapour pressure at 20°C is 2333.141 Pa
b). At 20°C, the pressure at atmospheric unit = 0.0231 atm
= 0.0231 x Pa
= 2310 Pa
Therefore,
= 0.99
Therefore percentage of atmospheric pressure = 0.99 x 100
= 99 %
c). We Know
Relative Humidity (Rh)=
where is vapour pressure
Rh is given as 100% = 1
∴ 1 =
= 2333.141 Pa
Now humidity ratio is
, where is mass of vapour
is mass of air
Let the total pressure be Pa
Therefore, percentage of water vapour is 0.01485 x 100
= 1.4 %