To solve this problem we will apply the relationship between Newton's second law and Hooke's law, with which we will define the balance of the system. From the only unknown in that equation that will be the constant of the spring, we will proceed to find the period of vibration of the car.
We know from Hooke's law that the force in a spring is defined as
Here k is the spring constant and x the displacement
While by Newton's second law we have that the Weight can be defined as
Here m is the mass and g the gravity acceleration.
The total weight would be
Each spring takes a quarter of the weight, then
Since the system is in equilibrium the force produced by the weight in each spring must be equivalent to the force of the spring, that is to say
The period of a spring-mass system is given as
The total mass is equivalent as the sum of all the weights, then replacing we have that the Period is
Therefore the period of vibration of the car as it comes to rest after the four get in is 0.9635s
If the wave velocity and frequency of a wave are both doubled, the wavelength will remain <u>the same. </u>
<u />
The wavelength of a wave shows the spatial orientation of distance between two successive crest in a wave medium.
The wavelength λ is expressed by using the relation:
Now, if velocity and frequency of wave is both doubled, the wavelength will remain <u>the same.</u>
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Learn more about wavelength here:
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Answer:
so initial speed of the rock is 30.32 m/s
correct answer is b. 30.3 m/s
Explanation:
given data
h = 15.0m
v = 25m/s
weight of the rock m = 3.00N
solution
we use here work-energy theorem that is express as here
work = change in the kinetic energy ..............................1
so it can be written as
work = force × distance ...................2
and
KE is express as
K.E = 0.5 × m × v²
and it can be written as
F × d = 0.5 × m × (vf)² - (vi)² ......................3
here
m is mass and vi and vf is initial and final velocity
F = mg = m (-9.8) , d = 15 m and v{f} = 25 m/s
so put value in equation 3 we get
m (-9.8) × 15 = 0.5 × m × (25)² - (vi)²
solve it we get
(vi)² = 919
vi = 30.32 m/s
so initial speed of the rock is 30.32 m/s
I did a project on Wood vs aluminum baseball bats to see which ball would travel farther when hit. I don't know If you play sports or anything but it was very fun for me considering I enjoy playing the game. You just got to be able to hit a ball with a bat
Answer:
<em>10.46m/s</em>
Explanation:
Given
Distance = 5.58m
Required
magnitude of the velocity'
Using the equation of motion expressed as
v² = u² + 2gS
v² = 0 +2(9.8)(5.58)
v² = 109.368
v= √109.368
v = 10.46m/s
<em>Hence the magnitude of the velocity of the of the chain is 10.46m/s</em>