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fenix001 [56]
2 years ago
13

What is the total amount of heat required to completely melt 347 grams of ice at its melting point

Chemistry
2 answers:
jolli1 [7]2 years ago
8 0
In order to calculate the amount of heat energy required to melt 347 grams of ice, we need to will apply the equation:
Q = ml, where m is the mass of substance and l is its latent heat of fusion. For ice, the latent heat of fusion is 334 joules per gram. Therefore:
Q = 347 x 334
Q = 112,558 joules of energy
noname [10]2 years ago
7 0

$$\boxed{115.898{\text{ kJ}}}$$ of heat is required to completely melt 347 g ice.

Further explanation:

Latent heat  

The heat released or absorbed during the process of conversion physical state of a substance without altering the temperature is known as the latent heat.

The latent heat of fusion of ice is 334 J/g.

When the physical state changes from the solid phase to liquid phase then the amount of heat absorbed in this process to completely convert the solid into liquid without altering the temperature is known as the latent heat fusion.

The formula to calculate heat absorbed from latent heat of fusion is,

$${\text{q}}={\text{m}}{{\text{H}}_{\text{f}}}$$           …… (1)

Here,

q is heat absorbed.

m is mass of substance.

${{\text{H}}_{\text{f}}}$ is latent heat of fusion.

The mass of given ice is 347 g.

Substitute 347 g for m and 334 J/g for ${{\text{H}}_{\text{f}}}$ in equation (1).

$$\align{{\text{q}}&={\text{m}}{{\text{H}}_{\text{f}}}\cr&=\left( {347{\text{ g}}} \right)\left({334{\text{ J/g}}}\right)\cr&=115898{\text{ J}}\cr}$$

Learn more:

1. The difference between heat and temperature.:brainly.com/question/914750

2. Determine the process by which water enters into atmosphere?: <u>brainly.com/question/2037060 </u>

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: Latent, Heat, fusion, Latent heat of fusion, temperature, ice, water, vapors, equilibrium, heat required, melting, heat release, heat absorbed, 115.898 kJ.

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Natali5045456 [20]

The volume of chlorine required is 7.71 L.

The reaction between phosphorus and chlorine is:

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Therefore, 2  moles of P requires 5 moles of chlorine to react with it.

Given mass of P =3.39 g

Molar mass of P=30.97 g/mol

No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles

2  moles of P requires 5 moles of chlorine

0.109  moles of P will require 0.109 x 5/2 = 0.2725 moles of chlorine

According to ideal gas equation

PV=nRT

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5 0
1 year ago
A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. What is the weight/
lara31 [8.8K]

Answer:

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. The weight/weight % or percent by mass of the solute is :

<u>2.67%</u>

Explanation:

Note : Look at the density of potassium nitrate in water if given in the question.

<u><em>You are calculating </em></u><u><em>weight /Volume</em></u><u><em> not weight/weight % or percent by mass of the solute</em></u>

Here the <u>weight/weight % or percent by mass</u> of the solute is asked : So first convert the<u> VOLUME OF SOLUTION into MASS</u>

Density of potassium nitrate in water KNO3 = 2.11 g/mL

density=\frac{mass}{volume}

Density = 2.11 g/mL

Volume of solution = 86.4 mL

2.11=\frac{mass}{86.4}

mass = 2.11\times 86.4

mass=182.3grams

Mass of Solute = 4.87 g

Mass of Solution = 183.2 g

w/w% of the solute =

= \frac{mass\ of\ solute}{mass\ of\ solution}\times 100

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Answer :

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