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scoundrel [369]
3 years ago
10

How many liters of 0.85 M HCl solution would react completely with 3.5 moles Ca(OH)2?

Chemistry
1 answer:
True [87]3 years ago
5 0
The reaction of Ca(oH)2 with HCl produces calcium chloride (CaCl2) and water (H2O). The stiochiometric equation is 2HCl + Ca(OH)2 = CaCl2 + 2H2O. In this case, 2 moles of HCl stoichiometrically reacts with one mole of calcium hydroxide. Hence for 3.5 moles of Ca(OH)2, there should be 1.75 moles of HCl needed. Given 0.85 M HCl, to get the volume, we divide 1.75 moles by 0.85 M. The volume needed is 2.0588 liters.
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4 years ago
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satela [25.4K]

Answer:

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2. Likely to form anions (except the noble gases).  

3. All of these  

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4 0
3 years ago
If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?
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Answer:

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Explanation:

Hello there!

In this case, since the radioactive decay kinetic model is based on the first-order kinetics whose integrated rate law is:

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k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{58year}=0.012year^{-1}

Therefore, we can next plug in the rate constant, elapsed time and initial mass of the radioactive to obtain:

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Regards!

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