R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3
HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
=-20/8
=-2.5
Explanation:
Given that,
Initial speed of the billiard ball 1, u = 30i cm/s
Initial speed of another billiard ball 2, u' = 40j cm/s
After the collision,
Final speed of first ball, v = 50 cm/s
Final speed of second ball, v' = 0 (as it stops)
Let us consider that both balls have same mass i.e. m
Initial kinetic energy of the system is :
Final kinetic energy of the system is :
The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :
So, the change in kinetic energy of the system as a result of the collision is equal to 0.
Answer:
See explanation.
Explanation:
If both stars explode in simultaneously in the <em>your </em>frame of reference then obviously you will see the two flashes simultaneously, and therefore, the time difference between the events would be zero.
If however, the stars exploded simultaneously in their frame of reference, then you would not observe the flashes simultaneously. Then the time difference between the events will not be zero, rather, you will observe star B exploding first and star A after.
Answer:
v = 8.90 km/h
Explanation:
In order to calculate the maximum collision speed of the 1200kg car, you take into account that the the kinetic energy of the car when it has a speed v, is equal to the potential elastic energy of the spring when it is maximum compressed.
Then, you use the following equation:
(1)
M: mass of the car = 1200kg
v: maximum collision speed of the car = ?
k: spring constant = 1.5MN/m = 1.5*10^6 N/m
x: maximum compression supported by the spring = 7.0cm = 0.070m
You solve the equation (1) for v and replace the values of the other parameters:
In km/h you obtain:
The maximum collision that the car can support is 8.90km/h
The answer is D. The temperature obviously doesnt rise slower or faster, and if you are heating an object, it would make no sense to say that less heat is being transferred.